关于无指定邻面的唯一3-可着色平面图
On uniquely 3-colorable plane graphs without prescribed adjacent faces
摘要：
一个图$G$是\emph{uniquely k-colorable}，如果$G$的色数是$k$，并且$G$只有一个$k$ -染色直到颜色的置换.对于平面图$G$，如果$d(f_1)=i$，$d(f_2)=j$和$f_1$和$f_2$有公共边，则$G$的两个面$f_1$和$f_2$是\emph{adjacent $(i,j)$-faces}，其中$d(f)$是面$f$的次数。本文证明了每一个唯一3-可染平面图都有相邻的$(3,k)$ -面，其中$k\leq 5$。$k$的边界5是最好的。进一步证明了存在一类唯一3-可着色的平面图，其中$i,j\in \{3,4,5\}$和$i \neq j$既不具有相邻的$(3,i)$-面，也不具有相邻的$(3,j)$ -面.我们的一个构造意味着存在一个无限族的边临界的唯一3-可着色的平面图，其中$n(\geq 11)$是奇数且$n\equiv 2\pmod{3}$具有$n$顶点和$\frac{7}{3}n-\frac{14}{3}$边.
英文摘要：
A graph $G$ is \emph{uniquely k-colorable} if the chromatic number of $G$ is $k$ and $G$ has only one $k$-coloring up to permutation of the colors. For a plane graph $G$, two faces $f_1$ and $f_2$ of $G$ are \emph{adjacent $(i,j)$-faces} if $d(f_1)=i$, $d(f_2)=j$ and $f_1$ and $f_2$ have a common edge, where $d(f)$ is the degree of a face $f$. In this paper, we prove that every uniquely 3-colorable plane graph has adjacent $(3,k)$-faces, where $k\leq 5$. The bound 5 for $k$ is best possible. Furthermore, we prove that there exist a class of uniquely 3-colorable plane graphs having neither adjacent $(3,i)$-faces nor adjacent $(3,j)$-faces, where $i,j\in \{3,4,5\}$ and $i \neq j$. One of our constructions implies that there exist an infinite family of edge-critical uniquely 3-colorable plane graphs with $n$ vertices and $\frac{7}{3}n-\frac{14}{3}$ edges, where $n(\geq 11)$ is odd and $n\equiv 2\pmod{3}$.
机构、总结、中文摘要均由AI分析而来，可能存在错误，请以论文正文为准。
