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arXiv 0901.1977math.GRmath.RA
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四元数代数中的自由群

Free Groups in Quaternion Algebras

S. O. Juriaans, A. C. Souza Filho

摘要:

在\cite{jpsf}中,我们构造了$\Q (\sqrt{-d})$上四元数代数的$\Z$ -阶中的单位对$u,v$,$d \equiv 7 \pmod 8$为正且无平方,使得$< u^ n,v^n>$对某些$n\in \mathbb{N}$是自由的.在这里,我们将这个结果推广到$\ \mathbb{Q}$的任何虚二次扩张,从而包括矩阵代数。更精确地说,我们证明了$< u^n,v^n> $对所有$n\geq 1$和$d>2$以及$d=2$和所有$n\geq 2$都是自由群。我们使用的单位来自佩尔和高斯方程。本文还建立了一个判定同胚对生成自由半群的准则,并证明了两个确定的单位生成一个自由半群,但在这种情况下,乒乓引理不能用来证明它们生成的群是自由的。

英文摘要:

In \cite{jpsf} we constructed pairs of units $u,v$ in $\Z$-orders of a quaternion algebra over $\Q (\sqrt{-d})$, $d \equiv 7 \pmod 8$ positive and square free, such that $< u^ n,v^n>$ is free for some $n\in \mathbb{N}$. Here we extend this result to any imaginary quadratic extension of $\ \mathbb{Q}$, thus including matrix algebras. More precisely, we show that $< u^n,v^n> $ is a free group for all $n\geq 1$ and $d>2$ and for $d=2$ and all $n\geq 2$. The units we use arise from Pell's and Gauss' equations. A criterion for a pair of homeomorphisms to generate a free semigroup is also established and used to prove that two certain units generate a free semigroup but that, in this case, the Ping-Pong Lemma can not be applied to show that the group they generate is free.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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