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arXiv 0709.0671math.NTmath.HO
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$e$的泰勒级数的哪些部分和可转化为$e$?(and a连接到素数2、5、13、37、463)、II

Which Partial Sums of the Taylor Series for $e$ are Convergents to $e$? (and a Link to the Primes 2, 5, 13, 37, 463), II

Jonathan Sondow, Kyle Schalm

摘要:

这是我们早期论文的扩展版本。设泰勒级数$e = \sum_{r=0}^{\infty} 1/r!$的第$n$次部分和为$A_n/n!$,$p_k/q_k$为$e$的简单连分式的第$k$次收敛.使用最近的措施,$e$的非理性,我们证明了我们的猜想,只有两个部分和的弱版本是converterable到$e$。证明了关于因子$q_k$和因子幂的一个相关结果。我们还发现了$A_n$和素数2、5、13、37、463之间令人惊讶的联系。在附录中,我们给出了一个条件证明的猜想,假设第二个猜想,我们对零的$A_n$和$q_k$模幂2。表支持这零猜想,我们讨论了2进重新制定它。

英文摘要:

This is an expanded version of our earlier paper. Let the $n$th partial sum of the Taylor series $e = \sum_{r=0}^{\infty} 1/r!$ be $A_n/n!$, and let $p_k/q_k$ be the $k$th convergent of the simple continued fraction for $e$. Using a recent measure of irrationality for $e$, we prove weak versions of our conjecture that only two of the partial sums are convergents to $e$. A related result about the denominators $q_k$ and powers of factorials is proved. We also show a surprising connection between the $A_n$ and the primes 2, 5, 13, 37, 463. In the Appendix, we give a conditional proof of the conjecture, assuming a second conjecture we make about the zeros of $A_n$ and $q_k$ modulo powers of 2. Tables supporting this Zeros Conjecture are presented and we discuss a 2-adic reformulation of it.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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