arXivDaily arXiv每日学术速递 周一至周五更新
arXiv周末暂无论文更新,休息一下吧,周末愉快~~
arXiv math/0011013math.AGmath.RAmath.RT
收藏

关于Deligne-Simpson问题

On the Deligne-Simpson problem

Vladimir Petrov Kostov

摘要:

Deligne-Simpson问题是这样表述的:给出选择共轭类$C_j\subset SL(n,{\bf C})$或$c_j\subset sl(n,{\bf C})$的充要条件,使得存在满足等式$M_1... M_{p+1}=I$或$A_1+... +A_{p+1}=0$的矩阵$M_j\in C_j$或$A_j\in c_j$的不可约$(p+1)$ -元组.我们解决了问题的通用特征值的情况下,矩阵$M_j$的情况下,当最大公约数的数量$Σ_{j,l}(σ)$的约旦块的一个给定的矩阵$M_j$,与一个给定的特征值$σ$和一个给定的大小$l$(采取所有$j$,$σ$,$l$)是$>1$。通有特征值由显式代数不等式定义。对于这样的特征值,不存在可约的$(p+1)$ -元组。矩阵$M_j$和$A_j$被解释为正则线性系统的单值算子和黎曼球面上的Fuchsian算子的矩阵剩余。

英文摘要:

The Deligne-Simpson problem is formulated like this: give necessary and sufficient conditions for the choice of the conjugacy classes $C_j\subset SL(n,{\bf C})$ or $c_j\subset sl(n,{\bf C})$ so that there exist irreducible $(p+1)$-tuples of matrices $M_j\in C_j$ or $A_j\in c_j$ satisfying the equality $M_1... M_{p+1}=I$ or $A_1+... +A_{p+1}=0$. We solve the problem for generic eigenvalues with the exception of the case of matrices $M_j$ when the greatest common divisor of the numbers $Σ_{j,l}(σ)$ of Jordan blocks of a given matrix $M_j$, with a given eigenvalue $σ$ and of a given size $l$ (taken over all $j$, $σ$, $l$) is $>1$. Generic eigenvalues are defined by explicit algebraic inequalities. For such eigenvalues there exist no reducible $(p+1)$-tuples. The matrices $M_j$ and $A_j$ are interpreted as monodromy operators of regular linear systems and as matrices-residua of fuchsian ones on Riemann's sphere.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑