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arXiv 2301.01552math.NT
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具有少数有理单生成化的序

Orders with few rational monogenizations

Jan-Hendrik Evertse

AI总结:

本文研究有理单生成序,证明了四次数域中具有多于两个有理单生成化的序仅有有限个,并推广至高次数域及 $S$-整数环情形。

摘要:

对于次数为 $n$ 的代数数 $α$,令 $\mathcal{M}_α$ 为由 $1,α,\ldots ,α^{n-1}$ 生成的 $\mathbb{Z}$-模;则 $\mathbb{Z}_α:=\{ξ\in\mathbb{Q} (α):\, ξ\mathcal{M}_α\subseteq\mathcal{M}_α\}$ 是 $\mathcal{M}_α$ 的标量环。我们称形如 $\mathbb{Z}_α$ 的序为有理单生成的。若 $α$ 是代数整数,则 $\mathbb{Z}_α=\mathbb{Z}[α]$ 是单生成的。有理单生成的序是二元形式不变序的特殊类型,已被广泛研究。若 $α,β$ 是两个 $\text{GL}_2(\mathbb{Z})$-等价的代数数,即对某 $\big(\begin{smallmatrix}a&b\c&d\end{smallmatrix}\big)\in\text{GL}_2(\mathbb{Z})$ 有 $β=(aα+b)/(cα+d)$,则 $\mathbb{Z}_α=\mathbb{Z}_β$。给定数域的序 $\mathcal{O}$,我们称满足 $\mathbb{Z}_α=\mathcal{O}$ 的 $α$ 的 $\text{GL}_2(\mathbb{Z})$-等价类为 $\mathcal{O}$ 的有理单生成化。我们证明以下结论。若 $K$ 是四次数域,则 $K$ 仅有有限个序具有多于两个有理单生成化。这是最佳可能结果。进一步,若 $K$ 是次数 $\geq 5$ 且其正规闭包的 Galois 群是 $5$-传递的数域,则 $K$ 仅有有限个序具有多于一个有理单生成化。证明使用了单位方程的有限性结果,而这些结果又是从 Schmidt 的子空间定理推导得出的。我们将上述结果推广到数域的 $S$-整数环上的有理单生成的序。我们的结果推广了 Bérczes、Győry 和作者在 2013 年关于多重单生成序的工作。

英文摘要:

For an algebraic number $α$ of degree $n$, let $\mathcal{M}_α$ be the $\mathbb{Z}$-module generated by $1,α,\ldots ,α^{n-1}$; then $\mathbb{Z}_α:=\{ξ\in\mathbb{Q} (α):\, ξ\mathcal{M}_α\subseteq\mathcal{M}_α\}$ is the ring of scalars of $\mathcal{M}_α$. We call an order of the shape $\mathbb{Z}_α$ \emph{rationally monogenic}. If $α$ is an algebraic integer, then $\mathbb{Z}_α=\mathbb{Z}[α]$ is monogenic. Rationally monogenic orders are special types of invariant orders of binary forms, which have been studied intensively. If $α,β$ are two $\text{GL}_2(\mathbb{Z})$-equivalent algebraic numbers, i.e., $β=(aα+b)/(cα+d)$ for some $\big(\begin{smallmatrix}a&b\\c&d\end{smallmatrix}\big)\in\text{GL}_2(\mathbb{Z})$, then $\mathbb{Z}_α=\mathbb{Z}_β$. Given an order $\mathcal{O}$ of a number field, we call a $\text{GL}_2(\mathbb{Z})$-equivalence class of $α$ with $\mathbb{Z}_α=\mathcal{O}$ a \emph{rational monogenization} of $\mathcal{O}$. We prove the following. If $K$ is a quartic number field, then $K$ has only finitely many orders with more than two rational monogenizations. This is best possible. Further, if $K$ is a number field of degree $\geq 5$, the Galois group of whose normal closure is $5$-transitive, then $K$ has only finitely many orders with more than one rational monogenization. The proof uses finiteness results for unit equations, which in turn were derived from Schmidt's Subspace Theorem. We generalize the above results to rationally monogenic orders over rings of $S$-integers of number fields. Our results extend work of Bérczes, Győry and the author from 2013 on multiply monogenic orders.

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