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arXiv 2108.05903math.STstat.TH
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自回归模型中残差经验分布函数的随机展开

On stochastic expansions of empirical distribution function of residuals in autoregression schemes

Michael Boldin

摘要:

考虑均值未知的平稳线性AR($p$)模型.自回归参数以及分布函数(d.f.)$G$的创新是未知的。观测值包含粗差(离群值)。离群值的分布未知且任意,其强度为$γn^{-1/2}$,$γ$未知,$n$为样本量。在这种情况下,最基本的问题是检验创新的正常性。正态性,如已知的,确保广泛使用的最小二乘程序的最优性。为了构造和研究Pearson卡方正态性检验,我们估计未知均值和自回归参数。然后,使用估计值,我们找到自回归中的残差。在此基础上,构造了一种经验分布函数(r.e.d. f.),这是(不可访问的)e.d.f.的对应物。自我回归的创新。我们的皮尔森饱和度是r.e.d.f.的函数。其渐近分布的假设和当地的替代决定的渐近行为的r.e.d.f.在目前的工作中,我们发现和证实的r.e.d. f的随机扩展的细节。在两种情况下。在第一个D。创新的$ G (x) $不依赖于$ n $。我们需要这个结果来研究假设下的检验统计量。在第二种情况下,$ G (x) $依赖于$ n $,并具有混合物的形式$ G (x) = A_n (x) = (1-n ^ {- 1/2}) G_0 (x) + n ^ { -1/2} H (x). $我们需要这个结果来研究本地替代品下的检验功效。

英文摘要:

We consider a stationary linear AR($p$) model with unknown mean. The autoregression parameters as well as the distribution function (d.f.) $G$ of innovations are unknown. The observations contain gross errors (outliers). The distribution of outliers is unknown and arbitrary, their intensity is $γn^{-1/2}$ with an unknown $γ$, $n$ is the sample size. The assential problem in such situation is to test the normality of innovations. Normality, as is known, ensures the optimality properties of widely used least squares procedures. To construct and study a Pearson chi-square type test for normality we estimate the unknown mean and the autoregression parameters. Then, using the estimates, we find the residuals in the autoregression. Based on them, we construct a kind of empirical distribution function (r.e.d.f.) , which is a counterpart of the (inaccessible) e.d.f. of the autoregression innovations. Our Pearson's satatistic is the functional from r.e.d.f. Its asymptotic distributions under the hypothesis and the local alternatives are determined by the asymptotic behavior of r.e.d.f. In the present work, we find and substantiate in details the stochastic expansions of the r.e.d.f. in two situations. In the first one d.f. $ G (x) $ of innovations does not depend on $ n $. We need this result to investigate test statistic under the hypothesis. In the second situation $ G (x) $ depends on $ n $ and has the form of a mixture $ G (x) = A_n (x) = (1-n ^ {- 1/2}) G_0 (x) + n ^ { -1/2} H (x). $ We need this result to study the power of test under the local alternatives.

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