arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 2003.00687math.OA
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$L(\mathbb{Z}^2\rtimes SL_2(\mathbb{Z}))$中的极大Haagerup子代数

Maximal Haagerup subalgebras in $L(\mathbb{Z}^2\rtimes SL_2(\mathbb{Z}))$

Yongle Jiang

摘要:

证明了$L(SL_2(\textbf{k}))$是$\textbf{k}=\mathbb{Q}$的$L(\textbf{k}^2\rtimes SL_2(\textbf{k}))$中的极大HaagerupvonNeumann子代数.然后我们展示如何修改证明以处理$\textbf{k}=\mathbb{Z}$。证明的关键步骤是完整地描述$L(SL_2(\textbf{k}))$和$L^{\infty}(Y)\rtimes SL_2(\textbf{k})$之间的所有中间von Neumann子代数,其中$SL_2(\textbf{k})\curvearrowright Y$表示通过修改关系$ϕ\sim ϕ'$得到的代数作用$SL_2(\textbf{k})\curvearrowright \widehat{\textbf{k}^2}$的商,其中$ϕ$,$ϕ'\in \widehat{\textbf{k}^2}$和$ϕ'(x, y):=ϕ(-x, -y)$对于所有$(x, y)\in \textbf{k}^2$。作为一个副产品,我们显示$L(PSL_2(\mathbb{Q}))$是一个极大冯诺依曼子代数在$L^{\infty}(Y)\rtimes PSL_2(\mathbb{Q})$,特别是,$PSL_2(\mathbb{Q})\curvearrowright Y$是一个素行动,即它不承认非平凡的商行动。

英文摘要:

We prove that $L(SL_2(\textbf{k}))$ is a maximal Haagerup von Neumann subalgebra in $L(\textbf{k}^2\rtimes SL_2(\textbf{k}))$ for $\textbf{k}=\mathbb{Q}$. Then we show how to modify the proof to handle $\textbf{k}=\mathbb{Z}$. The key step for the proof is a complete description of all intermediate von Neumann subalgebras between $L(SL_2(\textbf{k}))$ and $L^{\infty}(Y)\rtimes SL_2(\textbf{k})$, where $SL_2(\textbf{k})\curvearrowright Y$ denotes the quotient of the algebraic action $SL_2(\textbf{k})\curvearrowright \widehat{\textbf{k}^2}$ by modding out the relation $ϕ\sim ϕ'$, where $ϕ$, $ϕ'\in \widehat{\textbf{k}^2}$ and $ϕ'(x, y):=ϕ(-x, -y)$ for all $(x, y)\in \textbf{k}^2$. As a by-product, we show $L(PSL_2(\mathbb{Q}))$ is a maximal von Neumann subalgebra in $L^{\infty}(Y)\rtimes PSL_2(\mathbb{Q})$; in particular, $PSL_2(\mathbb{Q})\curvearrowright Y$ is a prime action, i.e. it admits no non-trivial quotient actions.

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