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arXiv 1908.07737math.NT
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关于无穷乘积展开式中消失系数的一些结果

Some results on vanishing coefficients in infinite product expansions

Nayandeep Deka Baruah, Mandeep Kaur

摘要:

最近,M。D. Hirschhorn证明,如果$\sum_{n=0}^\infty a_nq^n := (-q,-q^4;q^5)_\infty(q,q^9;q^{10})_\infty^3$和$\sum_{n=0}^\infty b_nq^n:=(-q^2,-q^3;q^5)_\infty(q^3,q^7;q^{10})_\infty^3$,那么$a_{5n+2}=a_{5n+4}=0$和$b_{5n+1}=b_{5n+4}=0$。受Hirschhorn,D. Tang证明了一些可比较的结果,包括:如果$ \sum_{n=0}^\infty c_nq^n := (-q,-q^4;q^5)_\infty^3(q^3,q^7;q^{10})_\infty$和$\sum_{n=0}^\infty d_nq^n := (-q^2,-q^3;q^5)_\infty^3(q,q^9;q^{10})_\infty$,则$c_{5n+3}=c_{5n+4}=0$和$d_{5n+3}=d_{5n+4}=0$。本文证明了$a_{5n}=b_{5n+2}$,$a_{5n+1}=b_{5n+3}$,$a_{5n+2}=b_{5n+4}$,$a_{5n-1}=b_{5n+1}$,$c_{5n+3}=d_{5n+3}$,$c_{5n+4}=d_{5n+4}$,$c_{5n}=d_{5n}$,$c_{5n+2}=d_{5n+2}$,和$c_{5n+1}>d_{5n+1}$ .我们还记录了Tang未列出的其他一些可比结果。

英文摘要:

Recently, M. D. Hirschhorn proved that, if $\sum_{n=0}^\infty a_nq^n := (-q,-q^4;q^5)_\infty(q,q^9;q^{10})_\infty^3$ and $\sum_{n=0}^\infty b_nq^n:=(-q^2,-q^3;q^5)_\infty(q^3,q^7;q^{10})_\infty^3$, then $a_{5n+2}=a_{5n+4}=0$ and $b_{5n+1}=b_{5n+4}=0$. Motivated by the work of Hirschhorn, D. Tang proved some comparable results including the following: If $ \sum_{n=0}^\infty c_nq^n := (-q,-q^4;q^5)_\infty^3(q^3,q^7;q^{10})_\infty$ and $\sum_{n=0}^\infty d_nq^n := (-q^2,-q^3;q^5)_\infty^3(q,q^9;q^{10})_\infty$, then $c_{5n+3}=c_{5n+4}=0$ and $d_{5n+3}=d_{5n+4}=0$. In this paper, we prove that $a_{5n}=b_{5n+2}$, $a_{5n+1}=b_{5n+3}$, $a_{5n+2}=b_{5n+4}$, $a_{5n-1}=b_{5n+1}$, $c_{5n+3}=d_{5n+3}$, $c_{5n+4}=d_{5n+4}$, $c_{5n}=d_{5n}$, $c_{5n+2}=d_{5n+2}$, and $c_{5n+1}>d_{5n+1}$. We also record some other comparable results not listed by Tang.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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