arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 1702.01436q-bio.PEmath.CO
收藏

基于最大简约法的祖先序列重构

Ancestral sequence reconstruction with Maximum Parsimony

Lina Herbst, Mareike Fischer

摘要:

基因组遗传学的主要目标之一是基于现代数据(例如DNA比对)来估计祖先序列。估计一组给定物种的最后一个共同祖先的数据的一种方法是首先用某种树推理方法重建一棵系统发育树,然后在该树的基础上使用某种祖先状态推理方法。最著名的树推理和祖先序列推理的方法之一是最大简约法(MP)。在这篇手稿中,我们专注于这种方法和祖先状态推断完全分叉树。特别是,我们调查了一个猜想发表的查尔斯顿和钢在1995年关于物种的数量,需要有一个特定的状态,说$a$,在一个特定的网站,以便MP明确返回$a$作为一个估计的状态,最后的共同祖先。我们证明了所有偶数个字符的状态,这是在生物学中最相关的情况下的猜想。我们还表明,该猜想一般不成立的奇数字符状态,但也提出了一些积极的结果,这种情况下。

英文摘要:

One of the main aims in phylogenetics is the estimation of ancestral sequences based on present-day data like, for instance, DNA alignments. One way to estimate the data of the last common ancestor of a given set of species is to first reconstruct a phylogenetic tree with some tree inference method and then to use some method of ancestral state inference based on that tree. One of the best-known methods both for tree inference as well as for ancestral sequence inference is Maximum Parsimony (MP). In this manuscript, we focus on this method and on ancestral state inference for fully bifurcating trees. In particular, we investigate a conjecture published by Charleston and Steel in 1995 concerning the number of species which need to have a particular state, say $a$, at a particular site in order for MP to unambiguously return $a$ as an estimate for the state of the last common ancestor. We prove the conjecture for all even numbers of character states, which is the most relevant case in biology. We also show that the conjecture does not hold in general for odd numbers of character states, but also present some positive results for this case.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑