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arXiv 1701.02459math.GR
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The Congruence Subgroup Problem for the Free Metabelian group on $n\geq4$ generators

David El-Chai Ben-Ezra

英文摘要:

The congruence subgroup problem for a finitely generated group $Γ$ asks whether the map $\hat{Aut\left(Γ\right)}\to Aut(\hatΓ)$ is injective, or more generally, what is its kernel $C\left(Γ\right)$? Here $\hat{X}$ denotes the profinite completion of $X$. It is well known that for finitely generated free abelian groups $C\left(\mathbb{Z}^{n}\right)=\left\{ 1\right\}$ for every $n\geq3$, but $C\left(\mathbb{Z}^{2}\right)=\hat{F}_ω$, where $\hat{F}_ω$ is the free profinite group on countably many generators. Considering $Φ_{n}$, the free metabelian group on $n$ generators, it was also proven that $C\left(Φ_{2}\right)=\hat{F}_ω$ and $C\left(Φ_{3}\right)\supseteq\hat{F}_ω$. In this paper we prove that $C\left(Φ_{n}\right)$ for $n\geq4$ is abelian. So, while the dichotomy in the abelian case is between $n=2$ and $n\geq3$, in the metabelian case it is between $n=2,3$ and $n\geq4$.

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