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arXiv 1610.03029cs.CC
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SDP族的CSP反驳的下界

Lower bounds for CSP refutation by SDP hierarchies

Ryuhei Mori, David Witmer

摘要:

对于$k$元谓词$P$,当$m \gg n$ .在这种情况下,自然的算法任务是\emph{refutation}:找到一个证明,证明一个给定的随机实例是不可满足的。Allen等人最近的工作表明,使用SDP反驳CSP $(P)$的难度由参数$\mathrm{cmplx}(P)$确定,最小的$t$在满足$P$的分配上不存在$t$均匀分布。特别是,他们表明,CSP $(P)$与$m \gg n^{\mathrm{cmplx(P)}/2}$的随机实例可以有效地使用SDP反驳。在这项工作中,我们给出的证据表明,$n^{\mathrm{cmplx}(P)/2}$约束也\emph{necessary}反驳使用SDP。具体来说,我们表明,如果$P$支持$(t-1)$ -明智的均匀分布在满足的分配,然后Sherali-Adams $_+$和Lovász-Schrijver $_+$ SDP层次结构不能反驳随机实例CSP $(P)$在多项式时间的任何$m \leq n^{t/2-ε}$。

英文摘要:

For a $k$-ary predicate $P$, a random instance of CSP$(P)$ with $n$ variables and $m$ constraints is unsatisfiable with high probability when $m \gg n$. The natural algorithmic task in this regime is \emph{refutation}: finding a proof that a given random instance is unsatisfiable. Recent work of Allen et al. suggests that the difficulty of refuting CSP$(P)$ using an SDP is determined by a parameter $\mathrm{cmplx}(P)$, the smallest $t$ for which there does not exist a $t$-wise uniform distribution over satisfying assignments to $P$. In particular they show that random instances of CSP$(P)$ with $m \gg n^{\mathrm{cmplx(P)}/2}$ can be refuted efficiently using an SDP. In this work, we give evidence that $n^{\mathrm{cmplx}(P)/2}$ constraints are also \emph{necessary} for refutation using SDPs. Specifically, we show that if $P$ supports a $(t-1)$-wise uniform distribution over satisfying assignments, then the Sherali-Adams$_+$ and Lovász-Schrijver$_+$ SDP hierarchies cannot refute a random instance of CSP$(P)$ in polynomial time for any $m \leq n^{t/2-ε}$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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