arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 1601.06332math.CO
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无Diamond集族规模的一个上界

An upper bound on the size of diamond-free families of sets

Dániel Grósz, Abhishek Methuku, Casey Tompkins

摘要:

令$La(n,P)$是不包含$P$作为(弱)子集的$[n]=\{1,2,...,n\}$的子集族的最大大小。表示为$B_{2}$的菱形偏序集定义在四个元素$x,y,z,w$上,关系为$x<y,z$和$y,z<w$。$La(n,P)$已经被研究了许多偏序集,其中一个主要的开放问题是确定$La(n,B_{2})$。研究布尔格$2^{[n]}$中极大链上$[n]$子集族的平均集合数是一种富有成效的方法。我们使用的最大链的划分,并介绍了一种诱导方法,以表明$La(n,B_{2})\leq(2.20711+o(1))\binom{n}{\left\lfloor \frac{n}{2}\right\rfloor }$,改进早期界的$(2.25+o(1))\binom{n}{\left\lfloor \frac{n}{2}\right\rfloor }$的克莱默,马丁和年轻。

英文摘要:

Let $La(n,P)$ be the maximum size of a family of subsets of $[n]=\{1,2,...,n\}$ not containing $P$ as a (weak) subposet. The diamond poset, denoted $B_{2}$, is defined on four elements $x,y,z,w$ with the relations $x<y,z$ and $y,z<w$. $La(n,P)$ has been studied for many posets; one of the major open problems is determining $La(n,B_{2})$. Studying the average number of sets from a family of subsets of $[n]$ on a maximal chain in the Boolean lattice $2^{[n]}$ has been a fruitful method. We use a partitioning of the maximal chains and introduce an induction method to show that $La(n,B_{2})\leq(2.20711+o(1))\binom{n}{\left\lfloor \frac{n}{2}\right\rfloor }$, improving on the earlier bound of $(2.25+o(1))\binom{n}{\left\lfloor \frac{n}{2}\right\rfloor }$ by Kramer, Martin and Young.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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