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北美退伍军人节(Veterans Day),12 日无更新
arXiv 1402.5646math.COcs.DM
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关于饱和$k$ -Sperner系统

On Saturated $k$-Sperner Systems

Natasha Morrison, Jonathan A. Noel, Alex Scott

摘要:

给定一个集合$X$,一个集合$\mathcal{F}\subseteq\mathcal{P}(X)$被称为$k$-Sperner,如果它在集合包含下不包含一个长度为$k+1$的链,并且它是饱和的,如果它关于这个属性是最大的。Gerbner等人指出,如果$|X|$相对于$k$足够大,则饱和$k$-Sperner系统$\mathcal{F}\subseteq\mathcal{P}(X)$的最小尺寸为$2^{k-1}$。我们证明了存在$\varepsilon>0$使得对于每一个$k$和$|X| \geq n_0(k)$都存在一个饱和的$k$-Sperner系统$\mathcal{F}\subseteq\mathcal{P}(X)$,其基数至多为$2^{(1-\varepsilon)k}$ .如果对于每个$S\in\mathcal{P}(X)\setminus\mathcal{F}$,$\mathcal{F}\cup\{S\}$含有比$\mathcal{F}$更多的长度为$k+1$的链,则称集合$\mathcal{F}\subseteq \mathcal{P}(X)$是过饱和的$k$-Sperner系统. Gerbner等人证明,如果$|X|\geq k$,则最小的这样的集合包含$2^{k/2-1}$和$O\left(\frac{\log{k}}{k}2^k\right)$之间的元素。我们表明,如果$|X|\geq k^2+k$,那么下限是最好的可能,一个多项式因子。

英文摘要:

Given a set $X$, a collection $\mathcal{F}\subseteq\mathcal{P}(X)$ is said to be $k$-Sperner if it does not contain a chain of length $k+1$ under set inclusion and it is saturated if it is maximal with respect to this property. Gerbner et al. conjectured that, if $|X|$ is sufficiently large with respect to $k$, then the minimum size of a saturated $k$-Sperner system $\mathcal{F}\subseteq\mathcal{P}(X)$ is $2^{k-1}$. We disprove this conjecture by showing that there exists $\varepsilon>0$ such that for every $k$ and $|X| \geq n_0(k)$ there exists a saturated $k$-Sperner system $\mathcal{F}\subseteq\mathcal{P}(X)$ with cardinality at most $2^{(1-\varepsilon)k}$. A collection $\mathcal{F}\subseteq \mathcal{P}(X)$ is said to be an oversaturated $k$-Sperner system if, for every $S\in\mathcal{P}(X)\setminus\mathcal{F}$, $\mathcal{F}\cup\{S\}$ contains more chains of length $k+1$ than $\mathcal{F}$. Gerbner et al. proved that, if $|X|\geq k$, then the smallest such collection contains between $2^{k/2-1}$ and $O\left(\frac{\log{k}}{k}2^k\right)$ elements. We show that if $|X|\geq k^2+k$, then the lower bound is best possible, up to a polynomial factor.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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