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arXiv 1402.4093cond-mat.str-el
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无公度自旋密度波作为自旋轨道耦合的特征

Incommensurate spin density wave as a signature of spin-orbit coupling

Aaron Farrell, P. -K. Wu, Y. -J. Kao, T. Pereg-Barnea

备注：
Main Text: 5 pages, 3 figures. Supplementary material: 3 pages, 2 figures
发表信息：
Phys. Rev. B 94, 214424 (2016)
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摘要：

在接近半填充和强相互作用的极限下，哈伯德模型导出了自旋哈密顿量。在其原始各向同性形式下，这是具有反铁磁耦合$J$的海森堡模型。在正方形晶格上没有阻挫，基态是一个经典的反铁磁体，用公度序矢量${\bf Q}=(π,π)$表示。在这项工作中，我们表明，包含自旋轨道耦合（SOC）的费米子哈伯德模型的正方形晶格导致在半填充的强相互作用限制的无公度自旋密度波（ISDW）。在这个极限下，哈伯德模型得到了非对角的各向异性自旋哈密顿量，它表现出与经典基态一样的无公度自旋序。我们注意到，一个ISDW可以在系统中发现，无论自旋轨道耦合由于嵌套和晶格畸变。然而，这些效应通常可以通过实验探针识别。

英文摘要：

Close to half filling and in the limit of strong interactions the Hubbard model leads a spin Hamiltonian. In its original isotropic form this is the Heisenberg model with antiferromagnetic coupling $J$. On a square lattice there is no frustration and the ground state is a classical antiferromagnet denoted by the commensurate order vector ${\bf Q}=(π,π)$. In this work we show that the inclusion of spin orbit coupling (SOC) in the fermionic Hubbard model on a square lattice leads to an incommensurate spin density wave (ISDW) in the strong interactions limit at half filling. In this limit the Hubbard model leads to a non-diagonal and anisotropic spin Hamiltonian which exhibits the incommensurate spin order as its classical ground state. We note that an ISDW can be found in systems regardless of spin orbit-coupling due to nesting and lattice distortion. These effects, however, can usually be recognized by experimental probes.

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