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arXiv 0905.1310math-phmath.APmath.MP
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单半径球面平均变换的支撑定理

The support theorem for the single radius spherical mean transform

Mark Agranovsky, Peter Kuchment

摘要:

设f(x)属于L^p(R^n)且R>0.该变换被认为是在R^n中半径为R的(几乎)所有球面上对函数f进行积分。该算子已知是非内射的(通过傅立叶变换可以看出)。然而,可以容易地利用第一类贝塞尔函数构造的反例仅当p>2n/(n-1)时属于L^p。S.之前已经证明了这一点。Thangavelu的p不超过临界数2n/(n-1),变换确实是单射。在这篇文章中,支持定理证明,加强这一内射性的结果。也就是说,如果K是R^n中的凸有界区域,指数p不大于2n/(n-1),并且$f$在不与K相交的半径为$R$的球面上的(几乎)所有积分都等于零,则f在区域K的闭包中被支撑。事实上,凸性在这种情况下是一个太强的条件,并且结果对任何我们称之为R-凸域的区域都成立。

英文摘要:

Let f(x) belong to L^p(R^n) and R>0. The transform is considered that integrates the function f over (almost) all spheres of radius R in R^n. This operator is known to be non-injective (as one can see by taking Fourier transform). However, the counterexamples that can be easily constructed using Bessel functions of the 1st kind, only belong to L^p if p>2n/(n-1). It has been shown previously by S. Thangavelu that for p not exceeding the critical number 2n/(n-1), the transform is indeed injective. In this article, the support theorem is proven that strengthens this injectivity result. Namely, if K is a convex bounded domain in R^n, the index p is not above 2n/(n-1), and (almost) all the integrals of $f$ over spheres of radius $R$ not intersecting K are equal to zero, then f is supported in the closure of the domain K. In fact, convexity in this case is too strong a condition, and the result holds for any what we call an R-convex domain.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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