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arXiv 0903.0594math.CO
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阿达玛积与镶嵌

Hadamard Products and Tilings

Jong Hyun Kim

摘要:

Louis W. Shapiro给出了切比雪夫多项式的双线性生成函数的组合证明,等价于公式1/(1-ax-x^2)* 1/(1-bx-x^2)=(1-x^2)/(1-abx-(2+a^2+b^2)x^2 -abx^3+x^4),其中 * 表示Hadamard乘积。以类似的方式,通过考虑一个2 × n的矩形的平铺,其中顶行是1 × 1和1 × 2的砖块,底行是1 × 1和1 × n的砖块,我们找到了阿达玛乘积1/(1-ax-x^2)* x^m/(1-bx-x^n)的显式公式。

英文摘要:

Louis W. Shapiro gave a combinatorial proof of a bilinear generating function for Chebyshev polynomials equivalent to the formula 1/(1-ax-x^2) * 1/(1-bx-x^2) = (1-x^2)/(1-abx-(2+a^2+b^2)x^2 -abx^3+x^4), where * denotes the Hadamard product. In a similar way, by considering tilings of a 2 by n rectangle with 1 by 1 and 1 by 2 bricks in the top row, and 1 by 1 and 1 by n bricks in the bottom row, we find an explicit formula for the Hadamard product 1/(1-ax-x^2) * x^m/(1-bx-x^n).

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