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arXiv 0711.3173nucl-th
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14 N和10 B中的T=0有效相互作用

T=0 effective interaction in 14N and 10B

Nicole Vinh Mau

摘要:

我们计算了~(14)N和~(10)B的1+和3+ T=0态。在中子-质子RPA模型中,这两个原子核由同一组方程描述。我们首先表明,一个裸露的明尼苏达相互作用导致太弱的绑定在bothnuclees。此外,它不能在10 B中产生它应该产生的3+基态。包括介质效应作为中子-质子对之间的声子交换治愈了14 N中的解协,但仍给出10 B中的1+基态,3+作为激发态。Gogny有效相互作用的相同研究很好地再现了两种核的性质:与以前引入介质效应时相同的14 N一致,但现在10 B中的3+成为基态。这一成功表明,通过其密度依赖项的Gogny相互作用考虑到了一个三体的力量,在壳模型计算中,已被证明是必不可少的,给一个3+基态在10 B的存在。

英文摘要:

We have calculated the 1+ and 3+, T=0 states in 14N and 10B. In a neutron-proton RPA model these two nuclei are described by the same set of equations. We first show that a bare Minnesota interaction leads to too weak binding in bothnuclei. Furthermore it does not produce a 3+ ground state in 10B as it should. Including medium effects as an exchange of phonons between the neutron-proton pair cures the desagreement in 14N but still gives a 1+ ground state in 10B with the 3+ as an excited state. The same study with a Gogny effective interaction reproduces nicely the properties of both nuclei: same agreement in 14N as previously when medium effeccts were introduced but now the 3+ in 10B becomes the ground state. This success suggests that through its density dependent term the Gogny interaction takes account of the presence of a three-body force which, in a shell model calculation, has been shown to be essential to give a 3+ ground state in 10B.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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