arXivDaily arXiv每日学术速递 周一至周五更新
北美退伍军人节(Veterans Day),12 日无更新
arXiv quant-ph/0211139quant-ph
收藏

N比特纠缠指数与分类

N-qubit Entanglement Index and Classification

Ying Wu

摘要:

我们证明了所有的N-量子比特态可以被分为N个纠缠类,每个纠缠类都有一个纠缠指数$E=N-p=0,1,...,N-1$(E=0对应于一个完全分离的类),其中$p$表示正整数N的一个分区的群的数量。换句话说,对于具有$n_j\ge 1$和$N=\sum_{j=1}^{p}n_j$的N的任何分区$(n_1,n_2,...,n_p)$,表示$n_j-$量子比特的完全纠缠态的具有$ρ_{n_j}$的对应状态$ρ_{n_1}\bigotimesρ_{n_2}...\bigotimes ρ_{n_p}$的纠缠指数是$E(ρ_{n_1}\bigotimesρ_{n_2}...\bigotimes ρ_{n_p})=\sum_{j=1}^{p}(n_j-1)=N-p$。

英文摘要:

We show that all the N-qubit states can be classified as N entanglement classes each of which has an entanglement index $E=N-p=0,1,...,N-1$(E=0 corresponds to a fully separate class) where $p$ denotes number of groups for a partition of the positive integer N. In other words, for any partition $(n_1,n_2,...,n_p)$ of N with $n_j\ge 1$ and $N=\sum_{j=1}^{p}n_j$, the entanglement index for the corresponding state $ρ_{n_1}\bigotimesρ_{n_2}...\bigotimes ρ_{n_p}$ with $ρ_{n_j}$ denoting a fully entangled state of $n_j-$qubits is $E(ρ_{n_1}\bigotimesρ_{n_2}...\bigotimes ρ_{n_p})=\sum_{j=1}^{p}(n_j-1)=N-p$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑