Was Sierpinski right? IV
英文摘要：
We prove for any mu = mu^{< mu}< theta < lambda, lambda large enough (just strongly inaccessible Mahlo) the consistency of 2^mu = lambda-> [theta]^2_3 and even 2^mu = lambda-> [theta]^2_{sigma,2} for sigma < mu . The new point is that possibly theta > mu^+ .
机构、总结、中文摘要均由AI分析而来，可能存在错误，请以论文正文为准。
