arXivDaily arXiv每日学术速递 周一至周五更新
arXiv周末暂无论文更新,休息一下吧,周末愉快~~
arXiv math/0611551math.COmath.RA
收藏

无可逆横截子矩阵环上的列分块矩阵

Column-partitioned matrices over rings without invertible transversal submatrices

Stephan Foldes, Erkko Lehtonen

摘要:

令任何环上的$p \times q$矩阵$M$的列被划分成$n$块,$M = [M_1, ..., M_n]$。如果具有来自不同块$M_i$的列的$M$的$p \times p$子矩阵都不是可逆的,则存在可逆的$p \times p$矩阵$Q$和正整数$m \leq p$,使得$QM = [QM_1, ..., QM_n]$是简化的梯形形式,并且在几乎所有$m-1$块$QM_i$中,每列的最后一个$m$条目或者全为零或者它们包括非零非单位。

英文摘要:

Let the columns of a $p \times q$ matrix $M$ over any ring be partitioned into $n$ blocks, $M = [M_1, ..., M_n]$. If no $p \times p$ submatrix of $M$ with columns from distinct blocks $M_i$ is invertible, then there is an invertible $p \times p$ matrix $Q$ and a positive integer $m \leq p$ such that $QM = [QM_1, ..., QM_n]$ is in reduced echelon form and in all but at most $m-1$ blocks $QM_i$ the last $m$ entries of each column are either all zero or they include a non-zero non-unit.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑