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arXiv 2605.09293math.CO
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关于Hoang的两个猜想

On two conjectures of Hoàng

Lanzhou University(兰州大学);Minnan Normal University(闽南师范大学)

Hongzhang Chen, Kaiyang Lan, Wenlong Zhong

AI总结:

论文反驳了Hoang关于α(G)≤3的图是完美可分图的猜想,并证实了偶孔图是3可分图的猜想。

摘要:

一个图G被称为完美可分的,如果对于每一个诱导子图H,只要H至少有一条边,顶点集V(H)可以被分成两个集合A,B,使得H[A]是完美图,且B中的顶点的 clique 数小于H的 clique 数。可以轻易看出,完美可分图的色数至多为(ω(G)+1)选2。Hoang猜测每一个α(G)≤3的图都是完美可分的。我们推翻了这个猜想。同样,一个至少有一条边的图G被称为k-可分的,如果对于每一个诱导子图H,只要H至少有一条边,顶点集V(H)可以被分成k个集合,其中没有一个集合包含H的最大 clique。可以轻易看出,k-可分图的色数至多为k^{ω-1}。Hoang猜测每一个无偶孔图都是3-可分的。我们证实了这个猜想。

英文摘要:

A graph $G$ is said to be perfectly divisible if for every induced subgraph $H$ of $G$ with at least one edge, the vertex set $V(H)$ can be partitioned into two sets $A, B$ such that $H[A]$ is perfect and $ω(B) < ω(H)$. It is easy to see that the chromatic number of a perfectly divisible graph is at most $\binom{ω(G)+1}{2}$. Hoàng conjectured that every graph $G$ with $α(G) \le 3$ is perfectly divisible. We disprove this conjecture. In the same vein, a graph $G$ with at least one edge is $k$-divisible if for every induced subgraph $H$ of $G$ with at least one edge, the vertex set $V(H)$ can be partitioned into $k$ sets, none of which contains a largest clique of $H$. It is easy to see that the chromatic number of a $k$-divisible graph is at most $k^{ω-1}$. Hoàng conjectured that every even-hole-free graph is 3-divisible. We confirm this conjecture.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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