$Sq^n$ 的纤维
The Fiber of $Sq^n$
AI总结：
研究$Sq^n$纤维的同调结构，通过Adams谱序列在$E_3$处折叠，确定$E_3=E_\infty$值，无需计算纤维的上同调或$E_2$项。
摘要：
一位同事询问了特定GEMs映射纤维中同调类的Adams滤出问题。arXiv:2105.02601v3 [math.AT]中证明的定理（定理4.4）有效回答了这一问题。我们展示这种及一些相关Adams谱序列都在$E_3$处折叠，并确定$E_3 = E_\infty$的值。值得注意的是，我们无需确定纤维的上同调或Adams谱序列的$E_2$项即可完成此工作。
英文摘要：
A colleague asked about the Adams filtrations of the homotopy classes in the homotopy of the fiber of a particular map between GEMs. The theorem proved in arXiv:2105.02601v3 [math.AT] proves to be effective in answering this (Theorem 4.4). We show that this and some related Adams spectral sequences all collapse at $E_3$ and we determine the value of $E_3 = E_\infty$. Notably, we do not need to determine the cohomology of the fiber or the $E_2$ term of the Adams spectral sequence to do this.
机构、总结、中文摘要均由AI分析而来，可能存在错误，请以论文正文为准。
