arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 2510.03445math.COcs.CGcs.DM
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关于几乎普通三角形数量的注记

Note on the Number of Almost Ordinary Triangles

Algoresearch L.L.C.(Algoreresearch有限责任公司);Research Institute of the University of Bucharest(布加勒斯特大学研究所);Alfréd Rényi Institute of Mathematics(阿尔弗雷德·雷尼数学研究所)

Adrian Dumitrescu, János Pach

AI总结:

研究平面上\(n\)个不共线点集\(X\)中\(c\) - 普通三角形数量。在特定条件下,证明其数量随\(n\)超线性甚至超二次增长,给出相关结论成立的条件,并提供计算\(n\)元点集中所有\(c\) - 普通三角形的\(O(n^{2.372})\)时间算法。

摘要:

设\(X\)是平面上\(n\)个点的集合,不全在一条直线上。根据盖莱 - 西尔维斯特定理,\(X\)总能张成一条普通直线,即恰好经过\(X\)中两个元素的直线。给定整数\(c\geq2\),由\(X\)张成的直线若经过\(X\)中至多\(c\)个点,则称为\(c\) - 普通直线。由\(X\)中三个不共线点张成的三角形,若其三条边所确定的直线都是\(c\) - 普通直线,则称为\(c\) - 普通三角形。受埃尔德什问题启发,富莱克等人证明存在绝对常数\(c\gt2\),使得若\(X\)不能被两条直线覆盖,则它至少确定一个\(c\) - 普通三角形,且此类三角形数量至少随\(n\)线性增长,他们提出该函数的真实增长率是否超线性的问题。我们证明若\(X\)不能被两条直线覆盖,且对于某个函数\(t(n)\to\infty\),没有直线经过\(X\)中超过\(n - t(n)\)个点,则\(X\)张成的\(17\) - 普通三角形数量至少是\(n\cdot t(n)\)的常数倍,即随\(n\)超线性增长,还表明\(t(n)\to\infty\)的假设是必要的。若进一步假设没有直线经过\(X\)中超过\(n/2 - t(n)\)个点,则\(17\) - 普通三角形数量随\(n\)超二次增长,若\(t(n)\)有界则该结论不成立。最后给出了一些算法结果,特别是为计算\(n\)元点集中所有\(c\) - 普通三角形提供了一个\(O(n^{2.372})\)时间的算法,其中\(c\lt n\)。

英文摘要:

Let $X$ be a set of $n$ points in the plane, not all on a line. According to the Gallai-Sylvester theorem, $X$ always spans an \emph{ordinary line}, i.e., one that passes through precisely 2 elements of $X$. Given an integer $c\ge 2,$ a \emph{line} spanned by $X$ is called \emph{$c$-ordinary} if it passes through at most $c$ points of $X$. A \emph{triangle} spanned by 3 noncollinear points of $X$ is called \emph{$c$-ordinary} if all 3 lines determined by its sides are \emph{$c$-ordinary}. Motivated by a question of Erd\H os, Fulek \emph{et al.}~\cite{FMN+17} proved that there exists an absolute constant $c > 2$ such that if $X$ cannot be covered by 2 lines, then it determines at least one $c$-ordinary triangle. Moreover, the number of such triangles grows at least linearly in $n$. They raised the question whether the true growth rate of this function is superlinear. We prove that if $X$ cannot be covered by 2 lines, and no line passes through more than $n-t(n)$ points of $X$, for some function $t(n)\rightarrow\infty,$ then the number of $17$-ordinary triangles spanned by $X$ is at least constant times $n \cdot t(n)$, i.e., superlinear in $n$. We also show that the assumption $t(n)\rightarrow\infty$ is necessary. If we further assume that no line passes through more than $n/2-t(n)$ points of $X$, then the number of $17$-ordinary triangles grows superquadratically in $n$. This statement does not hold if $t(n)$ is bounded. We close this paper with some algorithmic results. In particular, we provide a $O(n^{2.372})$ time algorithm for counting all $c$-ordinary triangles in an $n$-element point set, for any $c<n$.

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