arXiv 2011.075802020-11-15hep-ph

具有扩展Higgs扇区的经典标度不变模型的双环分析

Two-loop analysis of classically scale-invariant models with extended Higgs sectors

Johannes Braathen, Shinya Kanemura, Makoto Shimoda

备注：: 62 pages, 11 figures
DOI：: 10.1007/JHEP03(2021)297

摘要：

我们提出了第一个明确的计算领先的两个环路修正的Higgs三线性耦合$λ_{hhh}$的模型与经典标度不变性（CSI），使用有效势近似。此外，我们还研究-第一次在两个循环-CSI理论中的所有状态的质量之间出现的关系，由于正确再现125 GeV的希格斯玻色子质量的要求。除了获得一般CSI模型的分析结果，我们考虑两个特定的例子超越标准模型理论与扩展希格斯部门，即$N$ -标量模型（赋予全球$O(N)$对称性）和CSI版本的两希格斯双重模型，我们进行详细的数值研究这些情况。虽然在一个循环的希格斯三线性耦合的值是相同的，在所有CSI模型，并偏离约$82\%$从（一个循环）SM预测，我们发现，包括两个循环的校正升降机这种普遍性，并允许区分不同的BSM场景与CSI。考虑到微扰么正性和质量之间的关系的约束，我们发现对于这两种类型的情况下，我们认为在两个循环$λ_{hhh}$偏离其SM预测的$100\pm10\%$ -即一个相当显着的进一步偏离相对于一个循环的结果$\sim 82\%$。

英文摘要：

We present the first explicit calculation of leading two-loop corrections to the Higgs trilinear coupling $λ_{hhh}$ in models with classical scale invariance (CSI), using the effective-potential approximation. Furthermore, we also study -- for the first time at two loops -- the relation that appears between the masses of all states in CSI theories, due to the requirement of reproducing correctly the 125-GeV Higgs-boson mass. In addition to obtaining analytic results for general CSI models, we consider two particular examples of Beyond-the-Standard-Model theories with extended Higgs sectors, namely an $N$-scalar model (endowed with a global $O(N)$ symmetry) and a CSI version of the Two-Higgs-Doublet Model, and we perform detailed numerical studies of these scenarios. While at one loop the value of the Higgs trilinear coupling is identical in all CSI models, and deviates by approximately $82\%$ from the (one-loop) SM prediction, we find that the inclusion of two-loop corrections lifts this universality and allows distinguishing different BSM scenarios with CSI. Taking into account constraints from perturbative unitarity and the relation among masses, we find for both types of scenarios we consider that at two loops $λ_{hhh}$ deviates from its SM prediction by $100\pm10\%$ -- i.e. a quite significant further deviation with respect to the one-loop result of $\sim 82\%$.

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