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arXiv 2007.00736stat.MLcs.LGcs.NAmath.NA
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给定弱辅助信息下使用近线性样本的张量补全

Tensor Completion with Nearly Linear Samples Given Weak Side Information

Cornell University(康奈尔大学)

Christina Lee Yu, Xumei Xi

AI总结:

针对张量补全的计算—统计样本差距,本文提出利用各模式上与潜在因子非正交的弱权重向量,实现仅需近线性 $O(n^{1+κ})$ 样本的一致估计算法,并通过合成与真实数据验证。

摘要:

张量补全在执行张量估计所需样本数量方面表现出有趣的计算—统计差距。尽管一个具有 $n^t$ 个条目的 $t$ 阶张量仅有 $Θ(tn)$ 个自由度,但已知最佳的多项式时间算法需要 $O(n^{t/2})$ 个样本才能保证一致估计。本文证明,弱辅助信息足以将样本复杂度降至 $O(n)$。该辅助信息由每个模式的一个权重向量组成,且该向量与沿该模式的任一潜在因子均不正交;这一条件显著弱于假设已知含噪子空间。我们提出一种算法,利用该辅助信息,在任意小常数 $κ>0$ 下仅用 $O(n^{1+κ})$ 个样本即可产生一致估计量。我们还在合成数据集和真实世界数据集上进行了实验,验证了理论见解。

英文摘要:

Tensor completion exhibits an interesting computational-statistical gap in terms of the number of samples needed to perform tensor estimation. While there are only $Θ(tn)$ degrees of freedom in a $t$-order tensor with $n^t$ entries, the best known polynomial time algorithm requires $O(n^{t/2})$ samples in order to guarantee consistent estimation. In this paper, we show that weak side information is sufficient to reduce the sample complexity to $O(n)$. The side information consists of a weight vector for each of the modes which is not orthogonal to any of the latent factors along that mode; this is significantly weaker than assuming noisy knowledge of the subspaces. We provide an algorithm that utilizes this side information to produce a consistent estimator with $O(n^{1+κ})$ samples for any small constant $κ> 0$. We also provide experiments on both synthetic and real-world datasets that validate our theoretical insights.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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