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arXiv 1909.03027math.CO
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交换Cayley图的Meyniel极值族

Meyniel Extremal Families of Abelian Cayley Graphs

Fatemeh Hasiri, Igor Shinkar

摘要:

我们研究了警察和强盗的博弈,警察试图在图的顶点上抓住一个强盗。Meyniel猜想指出,对于$n$顶点上的每个连通图$G$,$G$的copnumber的上界为$O(\sqrt{n})$,即,$O(\sqrt{n})$足够抓住劫匪了我们提出了几个家庭的交换凯莱图是Meyniel极值,即,编号为$O(\sqrt{n})$的图形。这证明了Bradshaw证明的Cayley图的$O(\sqrt{n})$上界紧到一个乘法常数.特别是,这表明,Meyniel的猜想,如果真的,是紧的乘法常数,即使是阿贝尔凯莱图。为了证明这一结果,我们构造了$n$顶点上的Cayley图,其生成元是无$K_{2,3}$的$Ω(\sqrt{n})$.这表明Kövári,Sós,和Turán定理,说明任何$n$顶点的$K_{2,3}$ -free图最多有$O(n^{3/2})$边,即使是阿贝尔凯莱图也是紧到乘法常数的。

英文摘要:

We study the game of Cops and Robbers, where cops try to capture a robber on the vertices of a graph. Meyniel's conjecture states that for every connected graph $G$ on $n$ vertices, the cop number of $G$ is upper bounded by $O(\sqrt{n})$, i.e., that $O(\sqrt{n})$ suffice to catch the robber. We present several families of abelian Cayley graphs that are Meyniel extremal, i.e., graphs whose cop number is $O(\sqrt{n})$. This proves that the $O(\sqrt{n})$ upper bound for Cayley graphs proved by Bradshaw is tight up to a multiplicative constant. In particular, this shows that Meyniel's conjecture, if true, is tight to a multiplicative constant even for abelian Cayley graphs. In order to prove the result, we construct Cayley graphs on $n$ vertices with $Ω(\sqrt{n})$ generators that are $K_{2,3}$-free. This shows that the Kövári, Sós, and Turán theorem, stating that any $K_{2,3}$-free graph of $n$ vertices has at most $O(n^{3/2})$ edges, is tight up to a multiplicative constant even for abelian Cayley graphs.

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