arXivDaily arXiv每日学术速递 周一至周五更新
arXiv周末暂无论文更新,休息一下吧,周末愉快~~
arXiv 1807.03076math.CVmath.DGmath.GR
收藏

On the geometric order of totally nondegenerate CR manifolds

Masoud Sabzevari, Andrea Spiro

英文摘要:

A CR manifold $M$, with CR distribution $\mathcal D^{10}\subset T^\mathbb C M$, is called {\it totally nondegenerate of depth $μ$} if: (a) the complex tangent space $T^\mathbb C M$ is generated by all complex vector fields that might be determined by iterated Lie brackets between at most $μ$ fields in $\mathcal D^{10} + \overline{\mathcal D^{10}}$; (b) for each integer $2 \leq k \leq μ-1$, the families of all vector fields that might be determined by iterated Lie brackets between at most $k$ fields in $\mathcal D^{10} + \overline{\mathcal D^{10}}$ generate regular complex distributions; (c) the ranks of the distributions in (b) have the {\it maximal values} that can be obtained amongst all CR manifolds of the same CR dimension and satisfying (a) and (b) -- this maximality property is the {\it total nondegeneracy} condition. In this paper, we prove that, for any Tanaka symbol $\frak m = \frak m^{-μ}+ \ldots + \frak m^{-1}$ of a totally nondegenerate CR manifold of depth $μ\geq 4$, the full Tanaka prolongation of $\frak m$ has trivial subspaces of degree $k \geq 1$, i.e. it has the form $\frak m^{-μ}+ \ldots + \frak m^{-1} + \frak g^0$. This result has various consequences. For instance it implies that any (local) CR automorphism of a regular totally nondegenerate CR manifold is uniquely determined by its first order jet at a fixed point of the manifold. It also gives a complete proof of a conjecture by Beloshapka on the group of automorphisms of homogeneous totally nondegenerate CR manifolds.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑