arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 1708.01434math.CO
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关于并闭族的两个结果

Two Results on Union-Closed Families

Ilan Karpas

摘要:

我们表明,有一些绝对常数$c>0$,这样,对于任何并闭家庭$\mathcal{F} \subseteq 2^{[n]}$,如果\mbox{$|\mathcal{F}| \geq (\frac{1}{2}-c)2^n$},那么有一些元素$i \in [n]$出现在至少一半的集合$\mathcal{F}$。我们还表明,对于任何联合封闭的家庭$\mathcal{F} \subseteq 2^{[n]}$,集的数量不在$\mathcal{F}$,覆盖一组在$\mathcal{F}$是最多$2^{n-1}$,并提供例子,不等式是紧的。

英文摘要:

We show that there is some absolute constant $c>0$, such that for any union-closed family $\mathcal{F} \subseteq 2^{[n]}$, if \mbox{$|\mathcal{F}| \geq (\frac{1}{2}-c)2^n$}, then there is some element $i \in [n]$ that appears in at least half of the sets of $\mathcal{F}$. We also show that for any union-closed family $\mathcal{F} \subseteq 2^{[n]}$, the number of sets which are not in $\mathcal{F}$ that cover a set in $\mathcal{F}$ is at most $2^{n-1}$, and provide examples where the inequality is tight.

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