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arXiv 1606.09208math.CO
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部分价差的最大大小II:上界

The maximum size of a partial spread II: Upper bounds

Esmeralda Nastase, Papa Sissokho

摘要:

设$n$和$t$是正整数,且$t<n$,$q$是素数幂。${\rm PG}(n-1,q)$的部分$(t-1)$ -扩展是${\rm PG}(n-1,q)$的一组成对不相交的$(t-1)$ -维子空间.设$r\equiv n\pmod{t}$与$0\leq r<t$,并设$θ_i=(q^i-1)/(q-1)$。我们基本上证明,如果$2\leq r<t\leq θ_r$,那么${\rm PG}(n-1,q)$的部分$(t-1)$ -扩展的最大大小是由$(θ_n-θ_{t+r})/θ_t+q^r-(q-1)(t-3)+1$从上面有界的。当满足某些整除条件时,我们实际上给出了更严格的界限。这些界限改善了先前已知的${\rm PG}(n-1,q)$的最大尺寸部分($t-1$)-扩散的上限;例如,当$\lceil\frac{θ_r}{2}\rceil+4\leq t\leq θ_r$和$q>2$。本文作者最近确定了$t>θ_r$的最大尺寸部分$(t-1)$ -扩展的确切值(参见Ningestase-Sissokho [21])。

英文摘要:

Let $n$ and $t$ be positive integers with $t<n$, and let $q$ be a prime power. A partial $(t-1)$-spread of ${\rm PG}(n-1,q)$ is a set of $(t-1)$-dimensional subspaces of ${\rm PG}(n-1,q)$ that are pairwise disjoint. Let $r\equiv n\pmod{t}$ with $0\leq r<t$, and let $θ_i=(q^i-1)/(q-1)$. We essentially prove that if $2\leq r<t\leq θ_r$, then the maximum size of a partial $(t-1)$-spread of ${\rm PG}(n-1,q)$ is bounded from above by $(θ_n-θ_{t+r})/θ_t+q^r-(q-1)(t-3)+1$. We actually give tighter bounds when certain divisibility conditions are satisfied. These bounds improve on the previously known upper bound for the maximum size partial ($t-1$)-spreads of ${\rm PG}(n-1,q)$; for instance, when $\lceil\frac{θ_r}{2}\rceil+4\leq t\leq θ_r$ and $q>2$. The exact value of the maximum size partial $(t-1)$-spread has been recently determined for $t>θ_r$ by the authors of this paper (see Năstase-Sissokho [21]).

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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