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arXiv 1109.4971quant-ph
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一维自旋1 AKLT模型中两个块的负性

Negativity for two blocks in the one dimensional Spin 1 AKLT model

Raul A. Santos, V. Korepin, Sougato Bose

摘要:

本文计算了一维自旋为1的AKLT模型中两个长度分别为$L_A$和$L_B$的块之间的纠缠度,用负性来量化。我们采用了两种不同边界条件的模型。我们考虑的情况下,$N$自旋1在散装和一个自旋1/2在每个边界构成一个独特的基态,和的情况下,只有自旋1,即使在链的末端,其中的基态的简并度是4。在这两种情况下,我们都做了一个分区,由两个块$A$和$B$组成,分别包含$L_A$和$L_B$站点。这两个块的间隔是$L$。在这两种情况下,我们显式地获得了块$A$和$B$的约化密度矩阵。我们证明,在第一种情况下的负消失相同的$L\geq 1$,而在第二种情况下,它可能会接近一个常数$N=1/2$为每个简并本征态取决于一个构造这些本征态的方式。然而,由于在构造这些本征态时有一定的自由度,在后一种情况下,纠缠也可能消失。此外,我们还计算了自旋为1的AKLT模型在周期性边界条件下的非互补块之间的纠缠,其中有一个唯一的基态。即使在这种情况下,我们发现分离的自旋块的负性为零。

英文摘要:

In this paper we compute the entanglement, as quantified by negativity, between two blocks of length $L_A$ and $L_B$, separated by $L$ sites in the one dimensional spin-1 AKLT model. We took the model with two different boundary conditions. We consider the case of $N$ spins 1 in the bulk and one spin 1/2 at each boundary which constitute an unique ground state, and the case of just spins 1, even at the end of the chain, where the degeneracy of the ground state is four. In both scenarios we made a partition consisting of two blocks $A$ and $B$, containing $L_A$ and $L_B$ sites respectively. The separation of these two blocks is $L$. In both cases we explicitly obtain the reduced density matrix of the blocks $A$ and $B$. We prove that the negativity in the first case vanishes identically for $L\geq 1$ while in the second scenario it may approach a constant value $N=1/2$ for each degenerate eigenstate depending on the way one constructs these eigenstates. However, as there is some freedom in constructing these eigenstates, vanishing entanglement is also possible in the latter case. Additionally, we also compute the entanglement between non-complementary blocks in the case of periodic boundary conditions for the spin-1 AKLT model for which there is a unique ground state. Even in this case, we find that the negativity of separated blocks of spins is zero.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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