arXivDaily arXiv每日学术速递 周一至周五更新
arXiv math/0501366math.GM
收藏

有限分配格的同余表示中的并不可约数

On the number of join-irreducibles in a congruence representation of a finite distributive lattice

George Grätzer, Friedrich Wehrung

摘要:

对于有限格L,设EL表示L上的并依赖关系的自反闭包和传递闭包,定义在L的所有并不可约元的集合J(L)上。我们刻画的关系的形式EL,如下:定理。设E是有限集P上的拟序,则下列条件等价:(i)存在有限格L使得(J(L),EL)同构于拟序集(P,E). (ii)对于有限格L,设je(L)=| J(L)|-|J(Con L)|其中Con L是L的同余格.众所周知,不等式je(L)$\ge$ 0成立。对于有限的分配格D,我们定义并过剩函数:JE(D)= min(je(L))|D是D的一部分)。给出了有限分配格D的并过剩函数的计算公式。该公式意味着JE(D)$\le$(2/3)|J(D)|,对于任意有限分配格D,常数2/3是最佳可能的.这个公式的一个特例给出了有限下界格的同余格的一个刻划。

英文摘要:

For a finite lattice L, let EL denote the reflexive and transitive closure of the join-dependency relation on L, defined on the set J(L) of all join-irreducible elements of L. We characterize the relations of the form EL, as follows: Theorem. Let E be a quasi-ordering on a finite set P. Then the following conditions are equivalent: (i) There exists a finite lattice L such that (J(L),EL) is isomorphic to the quasi-ordered set (P,E). (ii) There are not exactly two elements x in P such that p E x, for any p in P. For a finite lattice L, let je(L) = |J(L)|-|J(Con L)|, where Con L is the congruence lattice of L. It is well-known that the inequality je(L) $\ge$ 0 holds. For a finite distributive lattice D, let us define the join-excess function: JE(D) = min(je(L) | Con L isomorphic to D). We provide a formula for computing the join-excess function of a finite distributive lattice D. This formula implies that JE(D) $\le$ (2/3)| J(D)|, for any finite distributive lattice D; the constant 2/3 is best possible. A special case of this formula gives a characterization of congruence lattices of finite lower bounded lattices.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑