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arXiv cs/0304023cs.CG
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将正多边形分成圆形部分 I:凸划分

Partitioning Regular Polygons into Circular Pieces I: Convex Partitions

Mirela Damian, Joseph O'Rourke

AI总结:

本文研究了正多边形的最优凸划分问题,证明等边三角形的最佳划分有无限多个部分,而正方形的最优长宽比差距缩小至0.01082。

摘要:

我们探讨了将多边形划分为每个部分尽可能‘圆形’的实例,即在意义上具有接近1的长宽比。多边形的长宽比是其最小外接圆直径与最大内切圆直径的比率。即使对于将正多边形划分为凸部分的问题,该问题也相当丰富,这是本文的重点。我们证明了等边三角形的最佳(最圆形)划分有无限多个部分,通过特定有限划分可以将下界逼近到任意精度。对于五边形和所有正k边形(k > 5),未划分的多边形已经是最佳的。正方形呈现出一个有趣的中间情况。在这里,单一部分的划分不是最优的,但也不是平凡下界可达到的。我们通过几种较为复杂的划分,将最优比率的长宽比差距缩小到0.01082。

英文摘要:

We explore an instance of the question of partitioning a polygon into pieces, each of which is as ``circular'' as possible, in the sense of having an aspect ratio close to 1. The aspect ratio of a polygon is the ratio of the diameters of the smallest circumscribing circle to the largest inscribed disk. The problem is rich even for partitioning regular polygons into convex pieces, the focus of this paper. We show that the optimal (most circular) partition for an equilateral triangle has an infinite number of pieces, with the lower bound approachable to any accuracy desired by a particular finite partition. For pentagons and all regular k-gons, k > 5, the unpartitioned polygon is already optimal. The square presents an interesting intermediate case. Here the one-piece partition is not optimal, but nor is the trivial lower bound approachable. We narrow the optimal ratio to an aspect-ratio gap of 0.01082 with several somewhat intricate partitions.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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