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具有完美完备性的4对1游戏的困难性

On the Hardness of $4$-to-$1$ Games with Perfect Completeness

Yumou Fei, Dor Minzer, Shuo Wang

arXiv 2610.12378首次发表:更新:

发表机构

Massachusetts Institute of Technology(麻省理工学院)

机构由 AI 辅助整理,请以论文原文为准。

AI 中文总结

该研究证实了4对1游戏猜想,证明区分具有完美完备性的4对1游戏的最优值为1和不超过ε是NP困难的,并由此推导出图着色与超图独立集问题的NP困难性结果。

AI 中文摘要

我们证明,对于所有ε>0,存在正整数k,使得给定字母大小至多为k的4对1游戏Ψ,区分val(Ψ)=1与val(Ψ)≤ε的问题是NP困难的。这证实了Khot在CCC 2002中提出的4对1游戏猜想。此前,Dinur、Khot、Kindler、Minzer和Safra取得的最佳结果确立了几乎完美完备性版本(但应用于更严格的2对1游戏问题)。利用文献中的结果,我们得到以下推论:(1) 对于所有k∈ℕ,给定一个3-可着色图G,找到其正确的k着色是NP困难的;(2) 对于所有δ>0,给定一个2-可着色3-均匀超图G,在其中找到包含至少δ比例顶点的独立集是NP困难的。我们的证明是一个三步构造,基于Dinur等人的两步框架:在外层PCP步骤中,我们使用二次方程获得完美完备性;然后构造一个新的中间PCP,执行低秩测试同时保留关键覆盖性质;最后,基于标准Grassmann编码的张量及其由Golowich在FOCS 2023提出的低秩变体,构造一个新的内层PCP。

英文摘要

We prove that for all $\varepsilon>0$, there exists a positive integer $k$ such that given a $4$-to-$1$ game $Ψ$ with alphabet size at most $k$, it is $\mathbf{NP}$-hard to distinguish between the case that $\mathrm{val}(Ψ)=1$ and the case that $\mathrm{val}(Ψ)\leq \varepsilon$. This confirms the $4$-to-$1$ Games Conjecture from [Khot, \textit{CCC 2002}]. Previously, the best known result, due to [Dinur, Khot, Kindler, Minzer, Safra], established the almost-perfect completeness version (but applied to the stricter problem of $2$-to-$1$ games). Using results from the literature, we get the following implications: (1) for all $k\in \mathbb{N}$, given a $3$-colorable graph $G$, it is $\mathbf{NP}$-hard to find a proper $k$-coloring; (2) for all $δ>0$, given a $2$-colorable $3$-uniform hypergraph $G$, it is $\mathbf{NP}$-hard to find in it an independent set containing at least $δ$ fraction of the vertices. Our proof is a three-step construction that builds on the two-step framework of [Dinur, Khot, Kindler, Minzer, Safra]. In the outer-PCP step, we use quadratic equations to gain perfect completeness. We then construct a new middle PCP that performs low-rank tests while preserving a key covering property. Finally, we construct a new inner PCP based on a tensor of the standard Grassmann encoding with its low-rank variant due to [Golowich, FOCS 2023].

论文原文

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