具有常数量曲率的Kähler--Ricci收缩子刚性
Kähler--Ricci Shrinkers with Constant Scalar Curvature Are Rigid
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中文总结 AI 辅助
本文证明常数量曲率的完备梯度Kähler--Ricci收缩子必为刚性的,即分解为Kähler--Einstein因子与欧氏空间之积,并给出一个黎曼刚性判据。
中文摘要 AI 辅助
设$(M^{2m},g,f,J)$为一个完备的梯度Kähler--Ricci收缩子,满足$\n\n\operatorname{Ric}+\nabla^2 f=\frac12 g$\n\n。我们证明,若数量曲率为常数,则该孤子是刚性的。更精确地说,存在整数$k\in\{0,\ldots,m\}$使得$R\equiv k$且$(M^{2m},g,J)\cong\bigl(N^{2k}\times\mathbb C^{m-k}, g_N+g_{\mathrm{Euc}},J_N\oplus J_0\bigr)$,其中$(N^{2k},g_N,J_N)$是Kähler--Einstein的且$\operatorname{Ric}_{g_N}=\frac12 g_N$。作为证明的一部分,我们建立了一个黎曼刚性判据:对于具有常数量曲率的完备非稳态梯度Ricci孤子,条件$\mathcal{L}_{\nabla f}\operatorname{Ric}=0$蕴含径向平坦性,从而蕴含刚性。
英文摘要
Let $(M^{2m},g,f,J)$ be a complete gradient Kähler--Ricci shrinker satisfying \[ \operatorname{Ric}+\nabla^2 f=\frac12 g. \] We prove that if the scalar curvature is constant, then the soliton is rigid. More precisely, there exists an integer $k\in\{0,\ldots,m\}$ such that \[ R\equiv k \] and \[ (M^{2m},g,J)\cong \bigl(N^{2k}\times\mathbb C^{m-k}, g_N+g_{\mathrm{Euc}},J_N\oplus J_0\bigr), \] where $(N^{2k},g_N,J_N)$ is Kähler--Einstein and \[ \operatorname{Ric}_{g_N}=\frac12 g_N. \] As part of the proof, we establish a Riemannian rigidity criterion: for a complete nonsteady gradient Ricci soliton with constant scalar curvature, the condition $\mathcal{L}_{\nabla f}\operatorname{Ric}=0$ implies radial flatness and hence rigidity.
发表机构
- East China Normal University(华东师范大学)
- Xiamen University(厦门大学)
- Zhejiang Sci-Tech University(浙江理工大学)
- Universidade Federal Fluminense(弗鲁米嫩塞联邦大学)
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