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arXiv 2609.28966math.CO

Hilton猜想及其推广的组合证明

A Combinatorial Proof of Hilton's Conjecture and Beyond

Thomas Lesgourgues, Luke Postle

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中文总结 AI 辅助

本文用精细吸收方法组合证明了Hilton猜想,即对足够大的n存在无子方阵拉丁方,并推广到高围长拉丁方及扩散分布。

中文摘要 AI 辅助

利用精细吸收方法,我们证明了对每个整数$g\ge 1$和实数$\gamma > 0$,以及足够大的$n$,存在一个$n^{-1+\gamma}$-扩散分布,作用于阶为$n$、围长至少为$g$且没有真子方阵的拉丁方上。这蕴含了20世纪70年代Hilton猜想(最近由Allsop和Wanless用代数方法证明)的一个组合证明,即对所有足够大的$n$,存在一个阶为$n$的无子方阵拉丁方;实际上,它蕴含至少存在$n^{(1-o(1))n^2}$个无子方阵拉丁方。同时,它也蕴含了高阶围长拉丁方的存在性(最近由Kwan、Sah、Sawhney和Simkin证明),甚至在高围长拉丁方上存在一个$n^{-1+\gamma}$-扩散分布。

英文摘要

Using refined absorption, we prove that for every integer $g\ge 1$ and real $γ> 0$, and for sufficiently large $n$, there exists an $n^{-1+γ}$-spread distribution on Latin squares of order $n$ and girth at least $g$ that have no proper subsquares. This implies a combinatorial proof of Hilton's conjecture from the 1970s (recently proved algebraically by Allsop and Wanless) that for all sufficiently large $n$, there exists a subsquare-free Latin square of order $n$; indeed, it implies there exist at least $n^{(1-o(1))n^2}$ subsquare-free squares. Simultaneously it also implies the existence of high girth Latin squares (recently proved by Kwan, Sah, Sawhney and Simkin) and even an $n^{-1+γ}$-spread distribution on high girth Latin squares.

发表机构

  • School of Mathematics and Statistics, University of New South Wales(新南威尔士大学数学与统计学院)
  • University of Waterloo(滑铁卢大学)

机构由 AI 辅助整理,请以论文原文为准。

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