arXivDaily arXiv每日学术速递 周一至周五更新
arXiv周末暂无论文更新,休息一下吧,周末愉快~~
arXiv 2609.23858math.PR

随机布尔张量幂在维度阈值处的线性独立性

Linear Independence of Random Boolean Tensor Powers at the Dimension Threshold

发表机构科罗拉多大学
查看机构详情
  • University of Colorado(科罗拉多大学)

机构由 AI 辅助整理,请以论文原文为准。

Kyle Luh

首次发表
浏览论文内容

中文总结 AI 辅助

该论文证明在维度阈值 $D(n,d)$ 下,随机布尔张量幂以高概率线性独立,误差为 $O_d(\log^{C_d} n / n^{1/2})$,解决了 Baldi 和 Vershynin 的开放问题。

中文摘要 AI 辅助

设 $d \geq 1$ 固定,令 $D(n,d):= \sum_{j=0}^{d} \binom{n-1}{j}$。我们证明,若 $x^{(1)}, \dots, x^{(m)}$ 是 $\{\pm 1\}^n$ 中的独立均匀点,则对 $m \leq D(n,d)$ 一致地,存在常数 $C_d > 0$,使得 $\mathbb{P}((x^{(1)})^{\otimes d}, \dots, (x^{(m)})^{\otimes d}$ 线性独立$)= 1 - O_d\left(\frac{\log^{C_d} n}{n^{1/2}} \right)$。这达到了精确的维度阈值,并回答了 Baldi 和 Vershynin 提出的问题。

英文摘要

Let $d \geq 1$ be fixed and let \[ D(n,d) := \sum_{j=0}^{d} \binom{n-1}{j}. \] We show that if $x^{(1)}, \dots, x^{(m)}$ are independent uniform points of $\{\pm 1\}^n$ then uniformly for $m \leq D(n,d)$, there exists a constant $C_d > 0$ such that \[ \mathbb{P}((x^{(1)})^{\otimes d}, \dots, (x^{(m)})^{\otimes d} \text{ are linearly independent}) = 1 - O_d\left(\frac{\log^{C_d} n}{n^{1/2}} \right). \] This achieves the exact dimensional threshold and answers a question asked by Baldi and Vershynin. We discuss applications of the result to the semidefinite relaxation of the cut-polytope and to matrix factorization.

补充信息

↑