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arXiv 2609.21577stat.ME

淘汰蒙特卡洛:均值-散布放行规则的精确接受概率

Phasing out Monte Carlo: exact acceptance probabilities for mean-spread release rules

Remus Osan

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中文总结 AI 辅助

针对均值-散布放行规则,提出用二维傅里叶反演精确计算接受概率,替代蒙特卡洛模拟与正态假设,并在非正态总体下验证其优于现有方法。

中文摘要 AI 辅助

一大类受监管的放行决策,当且仅当 $n$ 个单位的(样本均值,样本标准差)这一对值落在某个固定平面区域内时,才接受该生产批次。含量均匀度(USP <905>)、能力放行、变量抽样以及限内百分比高速公路验收均采用此形式。据我们所知,在当前实践中,假设的单位级分布下的接受概率并未被精确评估:对于一般的总体,$(\bar X,s)$ 的联合有限 $n$ 分布是一个受约束的 $n$ 重积分(Craig 1932 年针对 $n=3,4$;Springer 1953 年针对一般 $n$),该积分不存在初等化简。然而,该概率由加性对 $(T_1,T_2)=(\sum_{i=1}^{n} X_i,\sum_{i=1}^{n} X_i^2)$ 的分布决定,其特征函数是单观测变换的 $n$ 次幂。因此,一次二维傅里叶反演即可为任意光滑总体精确地(作为恒等式)并在数值上(在维度始终为二的网格上,无论 $n$ 取何值)给出该概率——这是对模拟和正态性假设的一种确定性替代方案。该恒等式是精确的;我们所评估的是其有限网格反演,其误差我们按示例报告而非给出界限。当 $n=3$ 且总体为均匀分布时,$(\bar X,s)$ 的联合分布、接受概率和能力分布可得到闭式解;我们推导出这些结果,将其用作验证阶梯的锚点,然后在非正态总体下以其规定的样本量($n=10$-$30$)端到端地处理三个规则。与精确答案相比,基于正态理论的现有方法所犯的误差足以改变计划所针对的风险,并且在工作曲线上两个方向都会出错,因此没有任何单一常数可以纠正它。一般而言,只有完整的分布才足够。

英文摘要

A large family of regulated release decisions accepts a production lot if and only if the pair (sample mean, sample standard deviation) of $n$ units falls in a fixed plane region. Content uniformity (USP <905>), capability release, variables sampling and percent-within-limits highway acceptance all take this form. The acceptance probability under a hypothesized unit-level law is not, so far as we are aware, evaluated exactly in current practice: for a general parent the joint finite-$n$ law of $(\bar X,s)$ is a constrained $n$-fold integral (Craig 1932 at $n=3,4$; Springer 1953 at general $n$) which admits no elementary reduction. Yet that probability is fixed by the law of the additive pair $(T_1,T_2)=(\sum_{i=1}^{n} X_i,\sum_{i=1}^{n} X_i^2)$, whose characteristic function is the $n$-th power of a one-observation transform. One two-dimensional Fourier inversion therefore delivers it for an arbitrary smooth parent - exactly, as an identity, and numerically on a grid whose dimension stays two whatever $n$ is - a deterministic alternative to both the simulation and the Normality assumption. The identity is exact; what we evaluate is a finite-grid inversion of it, whose error we report per example rather than bound. At $n=3$ the Uniform parent yields the joint law of $(\bar X,s)$, the acceptance probability and the capability law in closed form; we derive these, use them as the anchor of a validation ladder, and then work three rules end to end under non-normal parents at their prescribed sample sizes ($n=10$-$30$). Against the exact answer the Normal-theory incumbent errs by enough to change the risk a plan is designed against, and errs in both directions along the operating curve, so no single constant corrects it. In general only the full distribution suffices.

发表机构

  • Gilead Sciences(吉利德科学)

机构由 AI 辅助整理,请以论文原文为准。

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