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超越 $\tau_q$-半单性的 Baer 分裂

Baer Splitting Beyond $τ_q$-Semisimplicity

Xiaolei Zhang, Guocheng Dai

arXiv 2609.14338首次发表:更新:

发表机构

School of Mathematics and Statistics, Tianshui Normal University; School of Mathematical Sciences, Sichuan Normal University(天水师范学院数学与统计学院; 四川师范大学数学科学学院)

机构由 AI 辅助整理,请以论文原文为准。

AI 中文总结

本文证明 Baer 模均投射的环不一定是 $\tau_q$-半单环,通过非约化 Noether 环和约化凝聚 Bézout 环两类反例,推翻了原有猜想。

AI 中文摘要

对于交换环 $R$,若对挠 $R$-模 $T$ 有 $\Ext_R^1(B,T)=0$,则称 $R$-模 $B$ 为 Baer 模。已知当 $R$ 是 $\tau_q$-半单环(即其全商环是半单的环)时,每个 Baer 模都是投射的。曾有猜想认为其逆命题刻画了 $\tau_q$-半单环。我们证明该逆命题以两种本质上不同的方式失效。首先,在非约化 Noether 情形中,这种失效已是系统性的。若 $D$ 是非域的 Dedekind 整环且 $R=D[\varepsilon]/(\varepsilon^2)$,则每个 Baer $R$-模都是投射的,尽管 $R$ 不是约化的,因此不是 $\tau_q$-半单的。其次,即使在约化环中,事实上在约化凝聚 Bézout 环中,该逆命题也失效。主要工具是一个可数环判据。对于可数 Noether 整环 $D$,令 $\EC(D)$ 为 $D$ 上最终常值序列构成的环。若 $D$ 不是域,则每个 Baer $\EC(D)$-模都是投射的,而 $\EC(D)$ 是约化的且具有可数无穷多个极小素理想,因此不是 $\tau_q$-半单的。

英文摘要

For a commutative ring $R$, we call an $R$-module $B$ Baer if $\Ext_R^1(B,T)=0$ for torsion $R$-module $T$. It is known that every Baer module is projective when $R$ is $τ_q$-semisimple, i.e., rings whose total rings of quotients are semisimple. And it was conjectured that the converse characterizes $τ_q$-semisimple rings. We show that the converse fails in two substantially different ways. First, the failure is already systematic in the non-reduced Noetherian case. If $D$ is a Dedekind domain which is not a field and $R=D[\varepsilon]/(\varepsilon^2)$, then every Baer $R$-module is projective, although $R$ is not reduced, and thus is not $τ_q$-semisimple. Second, the converse fails even among reduced rings, and in fact among reduced coherent Bézout rings. The main tool is a countable-ring criterion. For a countable Noetherian domain $D$, let $\EC(D)$ be the ring of eventually constant sequences over $D$. If $D$ is not a field, then every Baer $\EC(D)$-module is projective, whereas $\EC(D)$ is reduced and has countably infinitely many minimal prime ideals, and thus is not $τ_q$-semisimple.

论文原文

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