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测试具有多项式查询复杂度的二元秩

Testing the Binary Rank with Polynomial Query Complexity

Michal Parnas

arXiv 2609.10496首次发表:更新:

发表机构

The Academic College of Tel Aviv-Yaffo(特拉维夫雅福学术学院)

机构由 AI 辅助整理,请以论文原文为准。

AI 中文总结

本文提出一种自适应双面误差测试算法,以多项式查询复杂度$O(d^3\log(d+1)/\epsilon^2)$测试$0,1$矩阵的二元秩,并支持近似二元分解,解决了开放问题。

AI 中文摘要

我们针对一个$0,1$矩阵$M$的二元秩提出了一种自适应双面误差测试算法,其查询复杂度为$O(d^3\log(d+1)/\epsilon^2)$,其中$d$是被测试的二元秩上界,$\epsilon$是距离参数。这回答了Parnas、Ron和Shraibman提出的一个开放问题,他们询问二元秩是否可以用关于$d$和$1/\epsilon$的多项式查询复杂度进行测试。此外,我们的测试算法可用于通过额外的$d(n+m)$次查询找到$M$的近似二元分解。也就是说,在保证$M$的二元秩至多为$d$的前提下,我们展示了如何以至少$5/6$的概率找到两个$0,1$矩阵$A',B'$,使得$M' = A' \cdot B'$是一个$0,1$矩阵,并且$M'$与$M$在至多$O(\epsilon)$比例的条目上不同。

英文摘要

We design an adaptive two-sided error testing algorithm for the binary rank of a $0,1$ matrix $M$ with query complexity $O(d^3\log(d+1)/ε^2)$, where $d$ is the tested binary rank bound and $ε$ is the distance parameter. This answers an open question posed by Parnas, Ron and Shraibman~\cite{parnas2021property}, who asked if the binary rank can be tested with query complexity polynomial in $d$ and $1/ε$. Furthermore, our testing algorithm can be used to find an approximate binary decomposition of $M$ with an additional $d(n+m)$ queries. That is, under the promise that the binary rank of $M$ is at most $d$, we show how to find, with probability at least $5/6$, two $0,1$ matrices $A',B'$ such that $M' = A' \cdot B'$ is a $0,1$ matrix which differs from $M$ on at most an $O(ε)$ fraction of its entries. Our results also imply a testing algorithm with polynomial query complexity for the equivalent problem of testing if the edges of a bipartite graph can be partitioned into at most $d$ bicliques.

论文原文

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