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多项式零点的$k$-卢卡斯环域

$k$-Lucas Annulus for Polynomial Zeros

Herbert Batte

arXiv 2608.26452首次发表:更新:

AI 中文总结

该研究证明关联$k$-卢卡斯与$k$-斐波那契序列的二项式恒等式,结合环域原理得到含$n$次复多项式零点的$k$-卢卡斯环域,补充相关基于$k$-斐波那契的界。

AI 中文摘要

我们证明了一个关联$k$-卢卡斯序列与$k$-斐波那契序列的二项式恒等式:对于实数$k>0$、整数$m\geq1$、$n\geq1$,当$n$为偶数时,$k$-卢卡斯数的二项式加权和可简化为$L_{k,mn}$的倍数;当$n$为奇数时,则可简化为$F_{k,mn}$的倍数。这种奇偶性依赖源于$k$-卢卡斯的比内公式缺少$k$-斐波那契数所具有的归一化因子$1/(\alpha-\beta)$。该恒等式针对$n$的每种奇偶性和每个$m$,提供了一族和为1的显式正权重;结合Dalal与Govil的一般环域原理,可得到一个包含所有$n$次复多项式零点的$k$-卢卡斯环域,补充了Díaz-Barrero、Bidkham-Shashahani及Kaur提出的基于$k$-斐波那契的界。

英文摘要

We prove a binomial identity relating the $k$-Lucas and $k$-Fibonacci sequences: for real $k>0$ and integers $m\ge1$, $n\ge1$, a binomial-weighted sum of $k$-Lucas numbers reduces to a multiple of $L_{k,mn}$ when $n$ is even, but to a multiple of $F_{k,mn}$ when $n$ is odd. This parity dependence traces back to the $k$-Lucas Binet formula lacking the normalising factor $1/(α-β)$ present for $k$-Fibonacci numbers. The identity supplies, for each parity of $n$ and each $m$, an explicit family of positive weights summing to one; combined with the general annulus principle of Dalal and Govil, this yields a $k$-Lucas annulus containing all the zeros of a complex polynomial of degree $n$, complementing the $k$-Fibonacci-based bounds of Díaz-Barrero, Bidkham-Shashahani, and Kaur.

CommentsThe k-Lucas sequence is a particular Horadam sequence, and the identity in Theorem 1.1 follows as a specialization of known binomial identities for Horadam sequences, which I had not seen at first

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