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随机泛型的等价性并非本质自由

Equivalence of Random Generics Is Not Essentially Free

Jason Zesheng Chen

arXiv 2608.21706首次发表:更新:

AI 中文总结

该研究针对ZFC模型上随机泛型的等价关系,结合Popa超刚性等工具证明其正测度限制不可弱归约到本质自由等价关系。

AI 中文摘要

设M为ZFC公理系统中足够大有限片段的可数传递模型,E^B_M是M上随机泛型的等价关系。Smythe证明了E^B_M不可Borel归约到M中任意可数群自由作用的轨道关系,并询问能否移除对目标群的限制。我们证明:若A是M上随机实数的正测度Borel集,F是本质自由的可数Borel等价关系,则从E^B_M在A上的限制(记为E^B_M↾A)到F的每个Borel同态,都将A的一个零测余子集映射到单个F等价类。因此,E^B_M的任何正测度限制都不是本质自由的,甚至无法弱Borel归约到本质自由关系。该证明结合了Thomas由Popa上同调超刚性导出的结论、2标记群的完美族,以及使用两个相继随机实数的富比尼论证。

英文摘要

Let $M$ be a countable transitive model of a sufficiently large finite fragment of ZFC, and let $E^{\mathbb B}_{M}$ be equivalence of random generics over $M$. Smythe proved that $E^{\mathbb B}_{M}$ is not Borel-reducible to the orbit relation of a free action of any countable group belonging to $M$, and asked whether the restriction on the target group can be removed. We prove that if $A$ is a positive-measure Borel set of random reals over $M$ and $F$ is an essentially free countable Borel equivalence relation, then every Borel homomorphism from $E^{\mathbb B}_{M}\upharpoonright A$ to $F$ maps a conull subset of $A$ into a single $F$-class. Hence no positive-measure restriction of $E^{\mathbb B}_{M}$ is essentially free, or even weakly Borel-reducible to an essentially free relation. The proof combines Thomas's consequence of Popa cocycle superrigidity with a perfect family of $2$-marked groups and a Fubini argument using two successive random reals.

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