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最大化给定阶数和边数的图的代数连通性:证明Kolokolnikov的一个猜想

Maximizing the algebraic connectivity of graphs of given order and size: a proof of a conjecture of Kolokolnikov

Sebastian M. Cioabă, Abhay Jayarajan, M. Rajesh Kannan, Rahul Roy

arXiv 2608.09879首次发表:更新:

AI 中文总结

本文针对图论领域,证明了Kolokolnikov于2015年提出的关于特定阶数和边数的图的最大代数连通性的猜想。

AI 中文摘要

图G的代数连通性是一种被广泛研究的图不变量,与图的连通性、扩张性等其他性质相关。给定n和m,α(n,m)是具有n个顶点、m条边的图的最大代数连通性。2015年,Kolokolnikov猜想当n≥3时,α(n,2n−4)=2,且通过计算验证了n≤12时该结论成立,本文证明了Kolokolnikov的这一猜想。

英文摘要

The algebraic connectivity of a graph $G$ is a well-studied graph invariant that is related to other properties of the graph such as connectivity and expansion. Given $n$ and $m$, $α(n,m)$ is the maximum algebraic connectivity of a graph with $n$ vertices and $m$ edges. In 2015, Kolokolnikov conjectured that $α(n,2n-4)=2$ for $n\geq 4$, and verified this claim computationally for $n \le 12$. In this paper, we prove Kolokolnikov's conjecture. We also show that $α(n,3(n-3)) = 3$ is false in general. %Combined with the computational verification for $n \le 12$, this yields $α(n,2n-4)=2$ for all admissible values of $n$.

CommentsCorrected minor typos and included the appendix

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