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用于暗物质搜寻的双碱金属共磁计中核子耦合比的最优无校准可观测量

Optimal Calibration-Free Observable for the Nucleon-Coupling Ratio in a Dual-Alkali Comagnetometer for Dark Matter Searches

Yossi Rosenzweig, Yevgeny Kats, Eli Sarid, Menachem Givon, Yonathan Japha, Ron Folman

arXiv 2608.07456首次发表:更新:

AI 中文总结

该研究针对双碱金属共磁计暗物质搜寻,将核子耦合比提取视为统计估计问题,确定最优无校准可观测量,明确不同频率下相位差与振幅比的精度表现及适用场景。

AI 中文摘要

双碱金属单胞$^{87}$Rb-$^{39}$K-$^{3}$He共磁计可通过两个光旋转通道读取类轴子暗物质信号,将场的中子与质子自旋耦合比$\boldsymbol{\textit{R}}=\boldsymbol{\textit{ξ}}_\boldsymbol{\textit{n}}/\boldsymbol{\textit{ξ}}_\boldsymbol{\textit{p}}$编码在相对响应中。跨物种相位差$\boldsymbol{\textit{Δφ}}$已被提出作为对$\boldsymbol{\textit{R}}$敏感的无校准读出量。将$\boldsymbol{\textit{R}}$的提取视为统计估计问题,我们证明最优可观测量是复通道间比值,其可拆分为$\boldsymbol{\textit{Δφ}}$和振幅比,其中仅$\boldsymbol{\textit{Δφ}}$对相对增益不敏感,因此是无校准的。对于所选共磁计参数,在~100 Hz以上,仅相位差就捕获了大部分耦合比信息;在更低频率下,$\boldsymbol{\textit{Δφ}}$并非近似充分统计量,此时振幅比可使$\boldsymbol{\textit{R}}$的精度提升至少2倍(在~40 Hz以下)。然而,恢复该信息需要足够准确地知晓相对增益,因此即使$\boldsymbol{\textit{Δφ}}$并非最优可观测量,它仍是稳健的可观测量。

英文摘要

A dual-alkali single-cell $^{87}$Rb-$^{39}$K-$^{3}$He comagnetometer can read an axionlike dark matter signal through two optical-rotation channels, encoding the ratio $\mathcal{R}=ξ_n/ξ_p$ of the field's neutron and proton spin couplings in their relative response. The inter-species phase difference $Δφ$ has been proposed as a calibration-free readout that is sensitive to $\mathcal{R}$. Treating the extraction of $\mathcal{R}$ as a statistical estimation problem, we show that the optimal observable is the complex inter-channel ratio, which splits into $Δφ$ and an amplitude ratio, of which only $Δφ$ is insensitive to the relative gain and hence calibration-free. For our choice of comagnetometer parameters, above $\sim\!100$ Hz the phase difference alone captures most of the coupling-ratio information. At lower frequencies $Δφ$ is not near-sufficient: there the amplitude ratio would improve the precision on $\mathcal{R}$ by a factor of $\gtrsim2$ below $\sim\!40$ Hz. Recovering that information, however, requires the relative gain to be known sufficiently accurately, so $Δφ$ stays the robust observable even where it is not the optimal one.

Comments13 pages, 3 figures

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