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arXiv 2607.25730math.GM

由三角形和一条截线形成的透视中心三角形

Perspective Central Triangles Formed from a Triangle and a Transversal

Stanley Rabinowitz, Ercole Suppa

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中文总结 AI 辅助

研究由三角形及截线形成的三个三角形放置固定中心后构成的中心三角形与原三角形何时透视,通过计算机搜索发现共点例子,给出外心等的证明及共点准则,刻画相关中心函数,表明共点与截线方向有关并研究特殊情况。

中文摘要 AI 辅助

设\(\ell\)是一条不经过三角形\(ABC\)任何顶点且不平行于任何边的直线。\(\ell\)分别与\(\triangle ABC\)的边\(BC\)、\(CA\)、\(AB\)交于点\(D\)、\(E\)、\(F\)。考虑形成的三个三角形:\(\triangle AEF\)、\(\triangle BFD\)和\(\triangle CDE\)。在这三个三角形中各放置一个固定的三角形中心(如内心、重心或垂心)确定一个“中心三角形”。研究参考三角形及其中心三角形何时透视,即直线\(AD\)、\(BE\)和\(CF\)何时共点。通过对三角形中心百科全书中前1000个中心的计算机搜索发现了许多共点例子。给出了外心、垂心和克劳森点的初等几何证明,建立了共点的一般准则,并确定了几种保持此性质的运算。主要结果是对其相关塞瓦线对每条截线\(\ell\)都共点的中心函数的完整刻画。还表明共点仅取决于截线的方向,并研究了截线平行于欧拉线的特殊情况。

英文摘要

Let $\ell$ be a line not passing through any vertex of a triangle $ABC$ and not parallel to any side. Line $\ell$ meets the sidelines $BC$, $CA$, $AB$ of $\triangle ABC$ at points $D$, $E$, $F$, respectively. We consider three of the triangles that are formed: $\triangle AEF$, $\triangle BFD$, and $\triangle CDE$. Placing a fixed triangle center (such as the incenter, centroid, or orthocenter) in each of these three triangles determines a \emph{central triangle}. We investigate when the reference triangle and its central triangle are perspective, i.e., when the lines $AD$, $BE$, and $CF$ are concurrent. A computer search over the first 1000 centers in the Encyclopedia of Triangle Centers suggested numerous examples of concurrence. We give elementary geometric proofs for the circumcenter, orthocenter, and Clawson point, develop a general criterion for concurrence, and identify several operations, including isogonal and isotomic conjugation, that preserve this property. Our main result is a complete characterization of the center functions whose associated cevians are concurrent for every transversal $\ell$. This yields an explicit normal form for such centers. We also show that concurrence depends only on the direction of the transversal, and we investigate the special case in which the transversal is parallel to the Euler line.

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