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无(\(P_2\cup P_3\))图的改进色数界

Explicit and logarithmically improved chromatic bounds for $(P_2\cup P_3)$-free graphs

Lizhong Chen

arXiv 2607.23441首次发表:更新:

发表机构

Hong Kong University of Science and Technology(香港科技大学)

机构由 AI 辅助整理,请以论文原文为准。

AI 中文总结

研究无(\(P_2\cup P_3\))图的色数界,通过证明\(\chi(G)\leq \binom{k + 2}{3} - \binom{k - 1}{2}\)给出改进方法,相比之前结果节省颜色并消除二次项,是对该图类界的首次改进。

AI 中文摘要

设\(G\)是无(\(P_2\cup P_3\))图,且\(k = \omega(G) \geq 4\)。我们证明了\(\chi(G)\leq \binom{k + 2}{3} - \binom{k - 1}{2} = \frac{k^3 + 11k - 6}{6}\)。此前Bharathi和Choudum给出的该无限制图类的最佳已知一般界是\(\chi(G)\leq\binom{k + 2}{3}\)。据我们所知,这是对其界的首次改进,适用于所有无(\(P_2\cup P_3\))图。结果节省了\(\binom{k - 1}{2}\)种颜色,消除了二次项。

英文摘要

We prove that every \((P_2\cup P_3)\)-free graph \(G\), with \(k=ω(G)\), satisfies \[ χ(G)=O\!\left(k^3\frac{\ln\ln k}{\ln k}\right). \] Thus the class admits an \(o(k^3)\) binding function. We also prove the explicit bound \[ χ(G)\le \frac{k^3}{8}+\frac{5k^2}{4}-4k+8 \qquad(k\ge8), \] with a sharper formula for odd \(k\). A further refinement gives an explicit cubic bound with leading coefficient \(104/837<1/8\).

Comments22 pages. Substantially rewritten and retitled, with a new $O(k^3\ln\ln k/\ln k)$ chromatic bound for the entire $(P_2\cup P_3)$-free class ($k=ω(G)$) and sharper explicit cubic bounds. The earlier row estimates and the quadratic bound under a rank-gap condition are not reproduced here; see v3 for those results

论文原文

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