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关于避免(132,213)的循环排列增长率的一个下界

A lower bound on the growth rate of $(132,213)$-avoiding cyclic permutations

Robert Laudone

arXiv 2607.21466首次发表:更新:

AI 中文总结

研究给出避免(132,213)的循环排列增长率的首个非平凡下界。构建新约简过程,迭代可判断是否为循环排列,反向能构建此类排列。还得出奇偶大小类双射及受限层数排列精确计数等结果。

AI 中文摘要

我们构建了一个新的约简过程,它将一个避免(132,213)的排列转化为一个更短的排列,当且仅当原排列是循环排列时新排列才是循环排列。通过迭代此过程可确定给定的避免(132,213)的排列是否为循环排列。反向操作可得到四个步骤,能从1(n为奇数时)或21(n为偶数时)唯一地构建出每个避免(132,213)的循环排列。主要应用是给出了\(\mathcal{C}_n(132,213)\)(长度为n且避免132和213的循环排列)增长率的首个非平凡下界。还给出了约简的其他一些结果,包括奇偶大小类之间的双射以及对具有受限层数排列的精确计数。

英文摘要

We construct a new reduction process which takes a $(132,213)$-avoiding permutation to a shorter one that is cyclic if and only if the original was. Iterating it determines whether a given $(132,213)$-avoiding permutation is cyclic. Reversing it gives four moves that build every cyclic $(132,213)$-avoiding permutation, uniquely, from $1$ if $n$ is odd, and $21$ if $n$ is even. Our main application is the first non-trivial lower bound for the growth rate of $\mathcal{C}_n(132,213)$, the cyclic permutations of length $n$ avoiding $132$ and $213$. We also give several other consequences of the reduction, including a bijection between the odd and even size classes and an exact enumeration for those permutations with a restricted number of layers.

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