涉及D.H. Lehmer数的华林问题
Waring's problem involving D.H. Lehmer numbers
AI总结:
本文证明每个充分大的整数,除非模16余15或16,可表示为14个D.H. Lehmer数的四次方之和;且每个充分大的整数可表示为16个D.H. Lehmer数的四次方之和。
摘要:
对于每个与奇素数$p$互素的正整数$a$,记$\overline{a}$为满足$1\leq \overline{a}\leq p$且$a\overline{a}\equiv 1(\mathrm{mod}~p)$的唯一整数。定义$$L(p)=\{a\in Z^+:(a,p)=1,2\nmid a+\overline{a}\}.$$ $L(p)$中的元素称为D.H. Lehmer数。本文的主要目的是证明:每个充分大的整数,除非它模16余15或16,均可表示为14个D.H. Lehmer数的四次方之和。此外,每个充分大的整数均可表示为16个D.H. Lehmer数的四次方之和。
英文摘要:
For every positive integer $a$ which is coprime with $p$, $p$ is an odd prime, we denote by $\overline{a}$ the unique integer satisfying $1\leq \overline{a}\leq p$ and $a\overline{a}\equiv 1(\mathrm{mod}~p)$. Put $$L(p)=\{a\in Z^+:(a,p)=1,2\nmid a+\overline{a}\}.$$ The elements of $L(p)$ are called D.H. Lehmer numbers. The main purpose of this paper is to prove that for any fixed odd prime $p$, every sufficiently large number unless it is congruent to 15 or 16$(\mathrm{mod}~{16})$ is representable as the sum of 14 fourth powers of D.H. Lehmer numbers. Furthermore, every sufficiently large number is representable as the sum of 16 fourth powers of D.H. Lehmer numbers.
机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。