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arXiv 1904.06012math.NAcs.DScs.NAmath.FAmath.PR
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少量迭代下的Lanczos算法:输出的集中与定位

The Lanczos Algorithm Under Few Iterations: Concentration and Location of the Output

Jorge Garza-Vargas, Archit Kulkarni

摘要:

研究了初始向量从$\mathbb{S}^{n-1}$中均匀采样的Lanczos算法。设$A$是一个$n \times n$厄米特矩阵。我们表明,当运行几次迭代,输出的Lanczos $A$几乎是确定性的。更确切地说,我们表明,对于任何$ \varepsilon \in (0, 1)$存在$c >0$只依赖于$\varepsilon$和$A$的频谱的某些全局属性(特别是,不依赖于$n$),使得当Lanczos运行在最多$c \log n$迭代,输出雅可比系数偏离其中位数$t$的概率最多$\exp(-n^\varepsilon t^2)$为$t<\Vert A \Vert$。对于Ritz值和向量,我们直接得到了类似的结果。我们的技术也产生渐近的结果:假设一个运行Lanczos的厄米特矩阵序列$A_n \in M_n(\mathbb{C})$,其谱分布收敛于Kolmogorov距离的速度$O(n^{-\varepsilon})$的密度$μ$的一些$\varepsilon > 0$。然后,我们表明,足够大的$n$,和$k=O(\sqrt{\log n})$,$k$迭代后输出的雅可比系数集中在那些$μ$。的渐近设置是相关的,因为Lanczos经常被用来近似的谱密度的一个无限维算子的雅可比系数的方式,我们的结果提供了一些理论依据,这种方法。在一个不同的方向,我们表明,Lanczos失败的概率很高,以确定异常值的频谱运行时,在大多数$c' \log n$迭代,其中再次$c'$仅取决于相同的全局属性的$A$频谱。经典的结果意味着,绑定$c' \log n$是紧到一个常数因子。

英文摘要:

We study the Lanczos algorithm where the initial vector is sampled uniformly from $\mathbb{S}^{n-1}$. Let $A$ be an $n \times n$ Hermitian matrix. We show that when run for few iterations, the output of Lanczos on $A$ is almost deterministic. More precisely, we show that for any $ \varepsilon \in (0, 1)$ there exists $c >0$ depending only on $\varepsilon$ and a certain global property of the spectrum of $A$ (in particular, not depending on $n$) such that when Lanczos is run for at most $c \log n$ iterations, the output Jacobi coefficients deviate from their medians by $t$ with probability at most $\exp(-n^\varepsilon t^2)$ for $t<\Vert A \Vert$. We directly obtain a similar result for the Ritz values and vectors. Our techniques also yield asymptotic results: Suppose one runs Lanczos on a sequence of Hermitian matrices $A_n \in M_n(\mathbb{C})$ whose spectral distributions converge in Kolmogorov distance with rate $O(n^{-\varepsilon})$ to a density $μ$ for some $\varepsilon > 0$. Then we show that for large enough $n$, and for $k=O(\sqrt{\log n})$, the Jacobi coefficients output after $k$ iterations concentrate around those for $μ$. The asymptotic setting is relevant since Lanczos is often used to approximate the spectral density of an infinite-dimensional operator by way of the Jacobi coefficients; our result provides some theoretical justification for this approach. In a different direction, we show that Lanczos fails with high probability to identify outliers of the spectrum when run for at most $c' \log n$ iterations, where again $c'$ depends only on the same global property of the spectrum of $A$. Classical results imply that the bound $c' \log n$ is tight up to a constant factor.

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