arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 1903.04773math.RA
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秩- $s$矩阵上相对小$s$的乘法导子

Multiplicative derivations on rank-$s$ matrices for relatively small $s$

Xiaowei Xu, Baochuan Xie, Yanhua Wang, Zhibing Zhao

摘要:

令$n$和$s$为固定整数,使得$n\geq 2$和$1\leq s\leq \frac{n}{2}$。设$M_n(\mathbb{K})$是域$\mathbb{K}$上所有$n\times n$矩阵的环。如果映射$δ:M_n(\mathbb{K})\rightarrow M_n(\mathbb{K})$对于任何两个秩- $s$矩阵$x,y\in M_n(\mathbb{K})$满足$δ(xy)=δ(x)y+xδ(y)$,则存在$M_n(\mathbb{K})$的导出$D$,使得$δ(x)=D(x)$对于每个秩- $k$矩阵$x\in M_n(\mathbb{K})$成立,其中$0\leq k\leq s$ .

英文摘要:

Let $n$ and $s$ be fixed integers such that $n\geq 2$ and $1\leq s\leq \frac{n}{2}$. Let $M_n(\mathbb{K})$ be the ring of all $n\times n$ matrices over a field $\mathbb{K}$. If a map $δ:M_n(\mathbb{K})\rightarrow M_n(\mathbb{K})$ satisfies that $δ(xy)=δ(x)y+xδ(y)$ for any two rank-$s$ matrices $x,y\in M_n(\mathbb{K})$, then there exists a derivation $D$ of $M_n(\mathbb{K})$ such that $δ(x)=D(x)$ holds for each rank-$k$ matrix $x\in M_n(\mathbb{K})$ with $0\leq k\leq s$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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