arXivDaily arXiv每日学术速递 周一至周五更新
arXiv周末暂无论文更新,休息一下吧,周末愉快~~
arXiv 1402.7362hep-th
收藏

稳定串钻头型号

Stable String Bit Models

Songge Sun, Charles B. Thorn

摘要:

在弦比特模型中,超弦以一个很长的“比特”链出现,其中s个费米子自由度对基态能量有正贡献,正好抵消了d=s个玻色子自由度的不稳定的负贡献。我们建议在弦比特模型类中非微扰地研究弦形成的物理,其中s>d,这样长链是稳定的,而不是边缘稳定的(s=d=8)超弦链。我们专注于这些模型中最简单的s=1和d=0,其中字符串位位于零空间维度。字符串位创建运算符是N X N矩阵。我们选择一个哈密顿量,使得大N极限产生在一维空间中运动的弦,激发对应于一个格拉斯曼光锥世界单场(s=1),没有玻色子世界单场(d=0)。我们研究这个模型在有限的N评估的作用,大N极限的出现的空间维度。结果表明,当N<(M-1)/2时,具有大比特数M的类弦态可能不存在.如果这是正确的,那么在有限N处可以有有限串比特链,但不是连续串。只有当N极大时,这样的链才能近似地表现为连续弦,在这种情况下,也会(近似地)出现一个新的空间维。在设计用来产生N=无穷大的临界超弦的弦比特模型中,我们只能期待在有限N处近似的洛伦兹不变性,其破坏阶数为1/N^2。

英文摘要:

In string bit models, the superstring emerges as a very long chain of "bits", in which s fermionic degrees of freedom contribute positively to the ground state energy in a way to exactly cancel the destabilizing negative contributions of d=s bosonic degrees of freedom. We propose that the physics of string formation be studied nonperturbatively in the class of string bit models in which s>d, so that a long chain is stable, in contrast to the marginally stable (s=d=8) superstring chain. We focus on the simplest of these models with s=1 and d=0, in which the string bits live in zero space dimensions. The string bit creation operators are N X N matrices. We choose a Hamiltonian such that the large N limit produces string moving in one space dimension, with excitations corresponding to one Grassmann lightcone worldsheet field (s=1) and no bosonic worldsheet field (d=0). We study this model at finite N to assess the role of the large N limit in the emergence of the spatial dimension. Our results suggest that string-like states with large bit number M may not exist for N<(M-1)/2. If this is correct, one can have finite chains of string bits, but not continuous string, at finite N. Only for extremely large N can such chains behave approximately like continuous string, in which case there will also be the (approximate) emergence of a new spatial dimension. In string bit models designed to produce critical superstring at N=infinity, we can then expect only approximate Lorentz invariance at finite N, with violations of order 1/N^2.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑